Ask question

Ask question

All categories

2 years ago

15

the mass of a mineral is 9.6g the mineral is placed in a graduated cylinder containing 8.o mL of water. the water level rises to

16.0 mL. what is the mineral's density?

2 answers:

Ray Of Light [21]2 years ago

6 0

The volume of the mineral = increase in volume of the water whuich is 16 - 8 = 8mls.

Therefore the mineral's density = 9.6 / 8

= 1.2 g/ ml answer

Anton [14]2 years ago

4 0

<h2>Answer:</h2>

The density of mineral is:

1.2 g/mL

<h2>Step-by-step explanation:</h2>

It is given that:

when a mineral with mass 9.6 g is placed in a cylinder with 8.0 mL of water then the water level rises to: 16.0 mL

This means that:

The volume of mineral is:

Volume of the water level after the mineral-Original volume of water in cylinder.

= 16-8

= 8 mL

Now, we know that the density of a substance is the ratio of mass to volume .

i.e.

$\text{Density}=\dfrac{\text{Mass}}{\text{Volume}}$

Hence, the density of substance will be:

$\text{Density}=\dfrac{9.6}{8}g/mL$

i.e.

$\text{Density}=1.2g/mL$

You might be interested in

Juana compró una camioneta 4x4 a S/ 42 000; además, sabe que la camioneta se depreciará (bajará su precio) en forma lineal duran

prohojiy [21]

Answer:

Una relación lineal es de la forma:

y = a*x + b.

donde a es la pendiente y b es la ordenada al origen.

en este caso, y es el precio de la camioneta, x es el numero de años que pasaron, a es la razon de depreciación de la camioneta y b es el precio inicial de la camioneta, b = $42,000.

Sabemos que después de 5 años, el precio de la camioneta es 21,000, entonces podemos resolver:

$21,000 = a*5 + $42,000

a*5 = $21,000 - $42,000 = -$21,000

a = -$21,000/5 = -$4,200

Esto significa que el precio decae $4,200 por año

4 0

2 years ago

True or false? If LM=MP, then M must be the midpoint of LP

Natalija [7]

I think that it's TRUE because it is in the middle when you draw the segment out

7 0

2 years ago

Read 2 more answers

An art curator records statistics about three new exhibits at her art museum. The mean age of the artifacts and the standard dev

pogonyaev

Definitely exhibit A

7 0

2 years ago

Read 2 more answers

The dot plots show the number of first cousins the boys and girls in Miss Campbell‘s class have. Based on the dot plot, which se

FromTheMoon [43]

Answer:

its the threed one.

Step-by-step explanation:

3 0

2 years ago

What is the perimeter of rhombus WXYZ?

oksian1 [2.3K]

<u>Answer</u>:

The perimeter of rhombus WXYZ is $4 \sqrt{13}$

<u>Step-by-step explanation:</u>

Step 1 :Finding length of XY

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =3

$y_1$ = -1

$y_2$ =2

XY = $\sqrt{(3-5)^2 +(2 -(-1))^2}$

XY = $\sqrt{(3-5)^2 +(2 +1))^2}$

XY = $\sqrt{(-2)^2 +(3))^2}$

XY = $\sqrt{4 +9}$

XY = $\sqrt{(13)}$

Step 2 :Finding length of YZ

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 3

$x_2$ =5

$y_1$ = 2

$y_2$ =5

YZ = $\sqrt{(5-3)^2 +(5-2)^2}$

YZ = $\sqrt{(2)^2 +(3)^2}$

YZ = $\sqrt{4 +9}$

YZ = $\sqrt{(13)}$

Step 3 : :Finding length of ZW

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =7

$y_1$ = 5

$y_2$ =2

ZW = $\sqrt{(7-5)^2 +(5-2)^2}$

ZW = $\sqrt{(2)^2 +(3)^2}$

ZW = $\sqrt{4 +9}$

ZW = $\sqrt{(13)}$

Step 4 :Finding length of WX

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 7

$x_2$ =5

$y_1$ = 2

$y_2$ = -1

WX = $\sqrt{(7-5)^2 +((-1)-2)^2}$

WX = $\sqrt{(2)^2 +(-3)^2}$

WX = $\sqrt{4 +9}$

WX = $\sqrt{(13)}$

Step 5: finding the perimeter of the rhombus

Perimeter= 4 X side

=> $4 \times \sqrt{13}$

=> $4 \sqrt{13}$

5 0

2 years ago

Read 2 more answers