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Gwar [14]
2 years ago
11

A small manufacturer constructs refrigerators. The fixed monthly cost is $200,000, and it costs $450 to produce one refrigerator

. The average cost function to produce X refrigerators is represented by: c(x)= 200,000+450x/x. What is the horizontal asymptote of C(x)?
Mathematics
2 answers:
kaheart [24]2 years ago
6 0

Answer: Horizontal asymptote of c(x) is 450.

Step-by-step explanation:

Since we have given that

Cost to produce one refrigerator = $450

Fixed monthly cost = $200,000

So, Average cost function to produce x refrigerators is given by

c(x)=\dfrac{200000+450x}{x}

Horizontal asymptote of c(x) would be

\dfrac{450x}{x}\\\\=450

Hence, Horizontal asymptote of c(x) is 450.

Kipish [7]2 years ago
3 0

Answer:

y=450

Step-by-step explanation:

It is given that the fixed monthly cost is $200,000, and it costs $450 to produce one refrigerator.

Total cost of x refrigerator is

T(x)=200,000+450x

The average cost function to produce X refrigerators is represented by:

C(x)=\dfrac{200,000+450x}{x}

If the degree of numerator and denominator are same, then horizontal asymptote is

y=\frac{p}{q}

where, p is the leading coefficient of numerator and q is leading coefficient of denominator.

In the above function leading coefficient of numerator is 450 and leading coefficient of denominator is 1. So, horizontal asymptote is

y=\frac{450}{1}

y=450

Therefore, the horizontal asymptote of C(x) is y=450.

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On her first day in a hospital, Kiri receives u1 milligrams (mg) of a therapeutic drug. The amount of the drug Kiri receives inc
Valentin [98]

Answer:

a. 21 = u1 + 6·d

b. 29 = u1 + 10·d

c. d = 2, u1 = 9

Step-by-step explanation:

a. The given parameters are;

The amount of therapeutic drug Kiri receives on her first at the hospital = u1 milligrams

The amount of drug increase received by Kiri each day = d

The amount of drug Kiri received on the seventh day = 21 mg

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aₙ = a₁ + (n - 1)·d

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a₁ = u1

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Therefore, for the 7th day, the amount of drugs she receives, which is 21 milligrams, is given as follows;

a₇ = u1 + (7 - 1)·d = u1 + 6·d = 21

The equation for the amount of drugs she receives in terms of u1 and d on the seventh day is given as follows;

21 = u1 + 6·d

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29 = u1 + 10·d

c. Therefore, we have two equations which are given as follows;

21 = u1 + 6·d................(1)

29 = u1 + 10·d..............(2)

Subtracting equation (1) from equation (2) gives;

29 - 21 = (u1 + 10·d) - (u1 + 6·d)

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From equation (1), we have;

21 = u1 + 6·d = u1 + 6×2 = u1 + 12

21 = u1 + 12

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d = 2, u1 = 9.

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