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2 years ago

Let r= 12 be the reserve rate. Which of the following is the money multiplier?

Mathematics

1 answer:

Studentka2010 [4]2 years ago

3 0

Answer:

Step-by-step explanation:

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A right cylinder has a radius of 2 units and height of 5 units.What is the volume of the cylinder? Round to the nearest tenth.

UkoKoshka [18]

V=hpir^2
r=2
h=5
pi≈3.141592

v=5*3.141592*2^2
v=5*3.141592*4
v=20*3.141592
v=62.83185307179586476925286766559
round to tenth
62.8 cubic units

8 0

1 year ago

Read 2 more answers

Alicia buys a 5 pound bag of rocks for a fish tank. She uses 1 1/8 pounds of small fish bowl. How much is left?

ipn [44]

5-1 and 1/8=
5-1-1/8=
4+1-1-1/8=
4-1+8/8-1/8=
3+7/8=
3 and 7/8 lb left

3 0

2 years ago

Read 2 more answers

Simplify the expression to a form in which 2 is raised to a single integer power. fraction numerator open parentheses 2 to the p

anzhelika [568]

Answer:

2^27

Step-by-step explanation:

Given the following expression:

[(2^10)^3 x (2^-10)] ÷ 2^-7

This can be easily simplified. Let us simplify the numerator first. To do that, we have

(2^10)^3 making use of the power rule of indices that says:

(A^a)^b = A^ab where a and b are powers, we have:

2^(10x3) = 2^30

Therefore the numerator becomes:

2^30 x 2^-10. Also making use of the multiplication rule that says:

A^a x A^b = A^(a + b), we have

2^30 x 2^-10 = 2^(30 – 10) = 2^20.

Now we have:

(2^20) ÷ (2^-7)

To simplify this, we need the division rule of indices which says:

A^a ÷ A^b = A^(a – b)

Therefore we have:

(2^20) ÷ (2^-7) = 2^[20 – (–7)] = 2^(20+7) = 2^27

5 0

1 year ago

For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: $z=\frac{x-\mu}{\sigma}$

Here z is 2.42 and μ is 790, substitute the respective values as shown.

$2.42=\frac{1637-790}{\sigma}$

$\sigma=\frac{847}{2.42}$

$\sigma=350$

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0

2 years ago

4. In the following diagram, STU, RTP and

Papessa [141]

Yea I don’t know sorry bye

6 0

2 years ago