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otez555 [7]
2 years ago
6

A painter is painting a wall with an area of 150 ft2. He decides to paint half of the wall and then take a break. After his brea

k, he paints half of the remaining unpainted portion and then takes another break. If he continues to paint half of the remaining unpainted portion between breaks, approximately what portion of the original wall will be painted when he takes his fifth break?
a. 112.50 ft2
b. 145.31 ft2
c. 147.66 ft2
d. 290.63 ft2
Mathematics
1 answer:
fgiga [73]2 years ago
3 0
First break= 1/2
second break = 1/2 of half= 1/4
third break = half of 1/4 = 1/8
forth break = 1/2 of 1/8 = 1/16
fifth break = 1/2 of 1/16 =1/32
fraction painted = 1 -1/32 =31/32
portion painted = 150*31/32 = 145.3125 ft^2
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Michelle receives 32K per year as an assistant fast food manager. Her benefits include health insurance, paid holidays, retireme
ryzh [129]

Answer:

The annual salary of Michelle including benefits = $48, 440

Step-by-step explanation:

<em>Since, you have not specified the table to show the value of each benefit.</em>

<em>So, I am assuming this table as the reference table to show the value of each benefit.</em>

<h3 /><h3><u>Benefits Value Table:</u></h3>

<h2>        Benefit                          Value</h2>

            Health Insurance                                 $7,550

            Paid Holidays                                       $660

            Retirement Contributions                    $4,500

            Paid Vacation                                        $1,230

            Uniform Supplied                                  $2,500

Here are the benefits details from the table:

Michelle receiving per year without benefits =  $32000

Health Insurance as benefit = $7,550

Paid Holidays  as benefit = $660

Retirement Contributions as benefit = $4,500

Paid Vacation as benefit = $1,230

Uniform Supplied as benefit = $2,500

So, the amount she gets from benefits = $7,550 + $660 + $4,500 + $1,230 + $2,500 = $16,440

So, the annual salary, including benefits could be calculated as:

Michelle receiving per year without benefits =  $32000

The amount Michelle gets from benefits = $16,440

Michelle have annual salary including benefits  = $32000 + $16,440

                                                                               = $48, 440

Hence, the annual salary of Michelle including benefits = $48, 440

Keywords: calculation, salary, benefits, saving

Learn more about salary calculation from brainly.com/question/5715627

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8 0
1 year ago
Mg+rg=2H, solve for g
Simora [160]

Answer:

g=\frac{2\,H}{m+r}

Step-by-step explanation:

Starting with :

m g + r g = 2 H

extract "g" as a common factor on the left of the equal sign:

g (m + r) = 2 H

Now, in order to solve for "g" , divide both sides of the equal sign by the binomial (m + r):

g = (2 H )/(m + r)

g=\frac{2\,H}{m+r}

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Which of the following are exterior angles , check all that apply?
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Answer:

The answer is just <6

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If p= (-2,7) find: Rx-axis(P)​
Nana76 [90]

Answer:

P(-2,7)

P'(-2,-7), ANSWER

reflection across the x-axis rule:

(×,y) ===> (x,-y)

Easy way to do this is draw the point on graph paper and count the same units above/below the x-axis. This example you are 7 units above the x-axis so you would count 7 units below the x-axis giving you the point.

6 0
2 years ago
Which of the following shows the extraneous solution to the logarithmic equation? log Subscript 4 Baseline (x) + log Subscript 4
vekshin1

<u>Given:</u>

The given equation is \log _{4}(x)+\log _{4}(x-3)=\log _{4}(-7 x+21)

We need to determine the extraneous solution of the equation.

<u>Solving the equation:</u>

To determine the extraneous solution, we shall first solve the given equation.

Applying the log rule \log _{c}(a)+\log _{c}(b)=\log _{c}(a b), we get;

\log _{4}(x(x-3))=\log _{4}(-7 x+21)

Again applying the log rule, if \log _{b}(f(x))=\log _{b}(g(x)) then f(x)=g(x)

Thus, we have;

x(x-3)=-7 x+21

Simplifying the equation, we get;

       x^2-3x=-7 x+21

       x^2+4x=21

x^2+4x-21=0

Factoring the equation, we get;

(x-3)(x+7)=0

Thus, the solutions are x=3, x=-7

<u>Extraneous solutions:</u>

The extraneous solutions are the solutions that does not work in the original equation.

Now, to determine the extraneous solution, let us substitute x = 3 and x = -7 in the original equation.

Thus, we get;

\log _{4}(3)+\log _{4}(3-3)=\log _{4}(-7 \cdot 3+21)

     \log _{4}(3)+\log _{4}(0)=\log _{4}(0)

Since, we know that \log _{a}(0) is undefined.

Thus, we get;

Undefined = Undefined

This is false.

Thus, the solution x = 3 does not work in the original equation.

Hence, x = 3 is an extraneous solution.

Similarly, substituting x = -7, in the original equation. Thus, we get;

\log _{4}(-7)+\log _{4}(-7-3)=\log _{4}(-7(-7)+21)

    \log _{4}(-7)+\log _{4}(-10)=\log _{4}(49+21)

    \log _{4}(-7)+\log _{4}(-10)=\log _{4}(70)

Simplifying, we get;

Undefined = \log _{4}(70)

Undefined = 3.06

This is false.

Thus, the solution x = -7 does not work in the original solution.

Hence, x = -7 is an extraneous solution.

Therefore, the extraneous solutions are x = 3 and x = -7

7 0
1 year ago
Read 2 more answers
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