day and night kennel charges $20 per day plus a food fee of $15 to board a pet. home away from home kennel charges $30 per day p
2 answers:
Answer:
Step-by-step explanation:
Let x represent the number of days. and y be the total cost.
We have been given that day and night kennel charges $20 per day, so charges for x days will be 20x.
We are also told that they charge food fee of $15 to board a pet, so total cost of boarding a pet in day and night kennel would be
The home away from home kennel charges $30 per day, so charges for x days will be 30x.
We are also told that they charge food fee of $5 to board a pet, so total cost of boarding a pet in day and night kennel would be
Therefore, our required system would be:
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Answer:
a) 5.5
b) None
Step-by-step explanation:
The given data set is {96,89,79,85,87,94,96,98}
First we must find the mean.
We now find the absolute value of the distance of each value from the mean.
This is called the absolute deviation
{}
{}
We now find the mean of the absolute deviations
The least absolute deviation is 1.5. This is not within one absolute deviation.
Therefore none of the data set is closer than one mean absolute deviation away from the mean.
Answer:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solutio to the problem
Let X the random variable that represent the amount of beer in each can of a population, and for this case we know the distribution for X is given by:
Where and
For this case we select 6 cans and we are interested in the probability that the total would be less or equal than 72 ounces. So we need to find a distribution for the total.
The definition of sample mean is given by:
If we solve for the total T we got:
For this case then the expected value and variance are given by:
And the deviation is just:
So then the distribution for the total would be also normal and given by:
And we want this probability:
And we can use the z score formula given by: