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dem82 [27]
2 years ago
12

A coin is flipped until 3 heads in succession occur. list only those elements of the sample space that require 6 or less tosses.

is this a discrete sample space? explain
Mathematics
1 answer:
Mashutka [201]2 years ago
6 0

we are given

A coin is flipped until 3 heads in succession occur

so, firstly, we will find sample space

S={HHH , THHH , HTHHH, TTHHH , TTTHHH , HTTHHH , THTHHH , HHTHHHH, ......}

now, we are given that

list only those elements of the sample space that require 6 or less tosses

so, we can see that sample space

S={HHH , THHH , HTHHH, TTHHH , TTTHHH , HTTHHH , THTHHH , HHTHHHH, ......}

There are infinite such possibilities

so, there are infinite number of elements in space

and we know that

discrete sample space will always have finite elements

but we have infinite number of sample space elements here

so, this is not discrete sample space...........Answer

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An article estimates, with 90% confidence, that the proportion of elementary school teachers who are female is 82%. The article
GREYUIT [131]

Answer:   (80% , 85%)

Step-by-step explanation:

We know that, confidence interval for population proportion is given by :-

(p-E , p+E)

, where p = sample proportion , E = Margin of error.

Given : Proportion of elementary school teachers who are female = 82%.

The article also states the maximum error of their estimate = 3%.

Then, the 90% confidence interval for the proportion of elementary school teachers who are female will be :

(82%-2% , 82%+3%)

= (80% , 85%)

Hence, the resulting 90% confidence interval for the proportion of elementary school teachers who are female = (80% , 85%)

5 0
2 years ago
When given a graph, the vertical line test can be used to determine functionality. Describe the vertical line test and explain t
just olya [345]

Answer:

When given a graph, the vertical line test can be used to determine functionality. The vertical line test would represent a function if no more than one point of the graph of a relation, this shows that only one output value for each input value. If this doesn't apply or more than one point is on the line then it would not represent a function.

Step-by-step explanation:

Draw vertical lines to intersect on a graph.

The relation is a function if there’s only one point of intersection on a graph.

The relation is not a function if there’s more than one point of intersection on a graph.

The vertical line test is used to determine if each input has exactly one output.

5 0
2 years ago
Read 2 more answers
Write H(t) for the amount spent in the United States on health care in year t, where t is measured in years since 2000. The rate
Kisachek [45]

Answer:

Check the explanation

Step-by-step explanation:

Write H(t) for the total sum spent in the United States on health care in year t, where t is measured in years since 2000.

The rate of increase of H(t) was projected to rise from $100 billion per year in 2000 to approximately $190 billion per year in 2010

(a) Find a linear model for the rate of change H'(t)

Slope of line is (190-100)/(2010-2000) = 90/10 = 9 billion dollars per yr

H'(t) - 190 = 9 (t-10) =

H'(t) = 9t + 100   billions dollars per year

(b) Given that $1,300 billion was spent on health care in the United States in 2000, find the function H(t).

H'(t) = 9t + 100   billions dollars per year   TAKING INTEGRATION..

H(t) = 9t^2/2 + 100t + C given H(0) = 1300

H(0) = 1300 = C

H(t) = 9t^2/2 + 100t + 1300 billion dollars.

5 0
2 years ago
Phil consumed 1,200 calories at lunch. He has a goal of burning at least 5% of those calories by walking on the treadmill. If wa
givi [52]

Answer: ** B **

  A. more than 18 minutes

~ B. no fewer than 18 minutes

  C. more than 3 hours

  D. no fewer than 3 hours

Step-by-step explanation:

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2 years ago
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In Exercises 1 and 2, find the equilibrium solutions of the differential equation specified.1) dy/dt = (y + 3)/(1 - y)2) dy/dt =
Aleks [24]

Answer:

1. Equilibrium solution: y= -3

2. Equilibrium solution y= ±1.414

Step-by-step explanation:

Thinking process:

The equilibrium solution can only be derived when \frac{dy}{dt}  = 0

1. Let's look at the first equation:

\frac{dy}{dt} = \frac{(y+3)}{(1-y)}

equating \frac{dy}{dt}  = 0 to the expression \frac{(y+3)}{(1-y)} gives

y + 3 = 0

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Therefore, the equilibrium solution occurs at y = -3

2. Let's look at the second solution:

\frac{dy}{dy} = \frac{(t^{2}- 1) (y^{2}-2) }{y^{2}-4 }

dividing each side by (t²-1) gives

1/(t²-1)\frac{dy}{dt} = (y²-2)/ (y²-4)

factorizing the right hand side gives:

at equilibrium:  \frac{dy}{dt}  = 0, then

y² - 2 = 0

solving for y gives y = ±√2

                                 = ±1.414

5 0
2 years ago
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