All categories

2 years ago

Text documents images audio clips and software applications are all examples of blank that are stored in files

Computers and Technology

2 answers:

Jlenok [28]2 years ago

8 0

These are all forms of data. More specifically, computer data.

pav-90 [236]2 years ago

7 0

They are all types of computer data stored in files.

You might be interested in

12) Suppose you wanted a subroutine to return to an address that was 3 bytes higher in memory than the return address currently

Snezhnost [94]

Answer:

.code

main proc

mov ecx,ebp

mov ecx, 787878

push ecx

call MySe7en

invoke ExitProcess,0

main endp

MySe7en PROC

pop ecx

sub ecx, 3

mov

push ecx

ret

end main

8 0

2 years ago

Consider a short, 10-meter link, over which a sender can transmit at a rate of 150 bits/sec in both directions. Suppose that pac

Katarina [22]

Answer:

The Tp value 0.03 micro seconds as calculated in the explanation below is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP.

Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

Explanation:

Given details are below:

Length of the link = 10 meters

Bandwidth = 150 bits/sec

Size of a data packet = 100,000 bits

Size of a control packet = 200 bits

Size of the downloaded object = 100Kbits

No. of referenced objects = 10

Ler Tp to be the propagation delay between the client and the server, dp be the propagation delay and dt be the transmission delay.

The formula below is used to calculate the total time delay for sending and receiving packets :

d = dp (propagation delay) + dt (transmission delay)

For Parallel downloads through parallel instances of non-persistent HTTP :

Bandwidth = 150 bits/sec

No. of referenced objects = 10

For each parallel download, the bandwith = 150/10

= 15 bits/sec

10 independent connections are established, during parallel downloads, and the objects are downloaded simultaneously on these networks. First, a request for the object was sent by a client . Then, the request was processed by the server and once the connection is set, the server sends the object in response.

Therefore, for parallel downloads, the total time required is calculated as:

(200/150 + Tp + 200/150 + Tp + 200/150 + Tp + 100,000/150 + Tp) + (200/15 + Tp + 200/15 + Tp + 200/150 + Tp + 100,000/15 + Tp)

= ((200+200+200+100,00)/150 + 4Tp) + ((200+200+200+100,00)/15 + 4Tp)

= ((100,600)/150 + 4Tp) + ((100,600)/15 + 4Tp)

= (670 + 4Tp) + (6706 + 4Tp)

= 7377 + 8 Tp seconds

Thus, parallel instances of non-persistent HTTP makes sense in this case.

Let the speed of propogation of the medium be 300*106 m/sec.

Then, Tp = 10/(300*106)

= 0.03 micro seconds

The Tp value 0.03 micro seconds as calculated above is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP. Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

4 0

2 years ago

Insert the appropriate functions in the Summary Statistics section of the worksheet: cells H18:H22. Format the payments with Acc

liberstina [14]

Answer:

Explanation:

If we want to insert the appropriate functions, we can know the operation, for example, it could be a sum, multiply, average or only divide, but if we want to apply for a format number like accounting number, we must go to the tab home and the section number, we can change the format number, an accounting or even text format.

8 0

2 years ago

An attacker has been successfully modifying the purchase price of items purchased on the company's web site. The security admini

Kruka [31]

Answer:

Form the given statement i have come to know that the by changing hidden form values attacker has been able to modify the purchase price.

Explanation:

User can change a hidden field is not different from a common field from browser or server side.

If you want to store data then user must have to store them on server -side on a session and it is a fastest way.

8 0

2 years ago

(1) Prompt the user to enter five numbers, being five people's weights. Store the numbers in an array of doubles. Output the arr

Mashutka [201]

Answer:

weights = []

total = 0

max = 0

for i in range(5):

weight = float(input("Enter weight " + str(i+1) + ": "))

weights.append(weight)

total += weights[i]

if weights[i] > max:

max = weights[i]

average = total / 5

print("Your entered: " + str(weights))

print("Total weight: " + str(total))

print("Average weight: " + str(average))

print("Max weight: " + str(max))

Explanation:

Initialize the variables

Create a for loop that iterates 5 times

Get the values from the user

Put them inside the array

Calculate the total by adding each value to the total

Calculate the max value by comparing each value

When the loop is done, find the average - divide the total by 5

Print the results

6 0

2 years ago