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Bas_tet [7]
2 years ago
3

Jesse used 5 gallons of gasoline to drive 50 miles. How much gasoline will he need to travel 170 miles?

Mathematics
2 answers:
just olya [345]2 years ago
5 0

5/50 = x / 170

solve for x by multiplying both sides by 170

Julli [10]2 years ago
3 0

50/5 = 10mpg

170/10 = 17 gallons

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Ms. berkin is dividing her 4 1/2-foot by 6-foot bulletin board into 4 sections with ribbon stretched from each corner to the opp
Mnenie [13.5K]

Answer:

15 feet.

Step-by-step explanation:

A bulletin board has been shown in the figure below.

Where the width of the board AB = DC = 4\frac{1}{2} = 4.5 feet

and the length of the board AD = BC = 6 feet

As Ms. Berkin is dividing the board by stretching the ribbons to the opposite corners so the length of ribbons will be AC and BD.

In right angle triangle <em>ADC</em>, using Pythagorean Theorem,

AC^2=AD^2+DC^2  = 6^2+4.5^2=36+20.25=56.25

AC= \sqrt{56.25} = 7.5 feet

Similarly in triangle <em>BDC</em>,

BD^2=BC^2+DC^2 = 6^2+4.5^2=36+20.25 =56.25

BD=\sqrt{56.25} = 7.5 feet

Thus, total length of the ribbon used = AC + BD = 7.5 + 7.5 = 15 feet

3 0
3 years ago
What are the x-intercepts of the function f(x) = –2x2 – 3x + 20?
Hatshy [7]

The root sof this quadratic equation are -4 and 2.5.


The roots of any quadratic can be found by using the quadratic equation. The equation is below for you.


\frac{-b +/- \sqrt{b^{2}- 4ac}}{2a}


In this equation you use the number attached to x^2 as the a, which in this case is -2. The number attached to x as b, which is in this case -3. And the number at the end as c, which is 20. From there you solve for the answers.


\frac{3 +/- \sqrt{-3^{2}- 4(-2)(20)}}{2(-2)}

\frac{3 +/- \sqrt{9 + 160}}{-4}

\frac{3 +/- 13}}{4}


Now you separate and get the two separate answers. First the positive.


\frac{3 + 13}}{4}

\frac{16}}{4}

4


Now the negative


\frac{3 - 13}}{4}

\frac{-10}}{4}

-2.5

5 0
2 years ago
Read 2 more answers
Two solutions of different concentrations of acid are mixed creating 40 mL of a solution that is 32% acid. One-quarter of the so
Georgia [21]
In order to construct this equation, we will use the variables:
V to represent mixture volume (40 ml)
C to represent mixture concentration (0.32)
v₁ to represent volume of first solution (40 / 4 = 10 ml)
c₁ to represent concentration of first solution (0.2)
v₂ to represent the volume of the second solution (40 * 3/4 = 30 ml)
c₂ to represent the concentration of the second solution 


We know that the total amount of substance, product of the volume and concentration, in the final solution is equal to the individual amounts in the two given solutions. Thus:
VC = v₁c₁ +  v₂c₂
40(0.32) = 10(0.2) + 30c
6 0
2 years ago
Read 2 more answers
What is the product? StartFraction 3 k Over k + 1 EndFraction times StartFraction k squared minus 1 Over 3 k cubed EndFraction S
Nana76 [90]

Answer:

StartFraction negative 1 Over k cubed EndFraction

Step-by-step explanation:

3k / (k + 1) × (k²- 1) / 3k³

= 3k(k² - 1) / (k + 1)(3k³)

= 3k³ - 3k / 3k⁴ + 3k³

= -3k / 3k⁴

= -1/k³

StartFraction k + 1 Over k squared EndFraction

(k + 1) / k²

StartFraction k minus 1 Over k squared EndFraction

(k - 1)/k²

StartFraction negative 1 Over k cubed EndFraction

= -1/k³

StartFraction 1 Over k EndFraction

= 1/k

4 0
1 year ago
Draw a graph of the rose curve. r = -3 sin 5θ, 0 ≤ θ ≤ 2π
kaheart [24]
Tada, Its on the Image. Hoped I helped :)

5 0
2 years ago
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