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SIZIF [17.4K]
2 years ago
11

There were 32 volunteers to donate blood. Unfortunately, n of the volunteers did not meet the health requirements, so they could

n't donate. The rest of the volunteers donated 470 milliliters each.
How many milliliters of blood did the volunteers donate?


WRITE ANSWER AS AN EXPRESSION
Mathematics
2 answers:
sergeinik [125]2 years ago
5 0

Answer:

Answer: The answer to this problem would be (32-n)*470!

Step-by-step explanation:

Since there were 32 volunteers the beginning and some of them couldn't donate you would subtract (the variable you would use is 'n'). As you may know, each means that you multiply so if each volunteer is giving 470 mm of blood each you would multiply that by how many volunteers are remaining which is unknown.

Your final answer would be: (32-n)*470

Hope this helps and gets Brainiest Answer!!!

Step-by-step explanation:

Tcecarenko [31]2 years ago
4 0

Answer:

<em>The volunteers donated  (15040-470n) milliliters of blood. </em>

Step-by-step explanation:

Total number of volunteers was 32 and the number of volunteers couldn't donate blood was n.

So, the <u>number of remaining volunteers who donated blood</u> will be: (32-n)

Each of these volunteers donated 470 milliliters blood.

So, the total amount of blood donated = 470(32-n) = (15040-470n) milliliters.

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luda_lava [24]

Answer:

In the figure ∠ABO and ∠BCO have measures equal to 35°.

Step-by-step explanation:

<u><em>The complete question is</em></u>

For circle O, m CD=125° and m∠ABC = 55°

In the figure<____, (AOB, ABO, BOA)  and <_____ (BCO, OBC,BOC) have measures equal to 35°

The picture in the attached figure

step 1

Find the measure of angle COB

we know that

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we have

arc\ CD=125^o

therefore

m\angle COB=125^o

step 2

we know that

AB is a tangent to the circle O at point A

so

ABC and ABO are right triangles

In the right triangle ABC

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Remember that

m\angle BCA+m\angle\ ABC=90^o ---> by complementary angles in a right triangle

we have

m\angle ABC=55^o

substitute

m\angle BCA+55^o=90^o

m\angle BCA=90^o-55^o=35^o\\

step 3

In the triangle BCO

Find the measure of angle CBO

we know that

m\angle CBO+m\angle COB+m\angle BCO=180^o ---> the sum of the interior angles in any triangle must be equal to 180 degrees

we have

m\angle COB=125^o

m\angle BCO=m\angle BCA=35^o -----> have measure equal to 35 degrees

substitute

m\angle CBO+125^o+35^o=180^o

m\angle CBO=180^o-160^o=20^o

step 4

Find the measure of angle ABO

In the right triangle ABO

we know that

m\angle ABC=m\angle CBO+m\angle ABO ----> by angle addition postulate

we have

m\angle ABC=55^o

m\angle CBO=20^o

substitute

55^o=20^o+m\angle ABO

m\angle ABO=55^o-20^o=35^o ----> have measure equal to 35 degrees

therefore

In the figure ∠ABO and ∠BCO have measures equal to 35°.

3 0
2 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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