Question

Tina has 15 pets they include Birds cats fish and hamsters she has twice as many hamsters as cats and together her pets have a total of 40 legs
how many of each kind of pet does Tina have

what percent of Tina pets are cats

Answer 1

Answer:

First answer

number of cats = 2

number of hamsters = 4

number of birds = 8

number of fishes = 1

Second answer

number of cats = 3

number of hamster = 6

number of  birds   =2

number of fishes =  4

Step-by-step explanation:

Let the number of cats be x . Let number of birds be y and Let number of fishes be z.

number of hamsters = 2 number of cats

                                    =2x

birds +cats + hamsters + fish = 15

 y +x +2x + z  = 15  

y +3x + z =  15

then number of hamsters = 2x

birds has legs = 2

hamster legs = 4

cats legs = 4

total legs  =40

2y+4x+4(2x) =40

2y+12x = 40

y+6x = 20   ,Since x ,y z are natural number   ,since x ,y and z are numbers of pets of each kind which have to be natural number ,therefore

Case 1 for y = 2   x = 3

for y = 8  x = 2

for y = 2 and x =3 ,we have

2+3(3) +z = 15

2+9+z = 15

11 +z = 15

 z = 15 -11 = 4

Case 2

for y= 8 and x=2 ,we have

8 +3(2) + z = 15

8 +6 +z = 15

   z =15-14 = 1

We have two answers for this problem

First answer

number of cats = 2

number of hamsters = 4

number of birds = 8

number of fishes = 1

Second answer

number of cats = 3

number of hamster = 6

number of  birds   =2

number of fishes =  4

For case 1   fish % =   $\frac{1}{15} x100$=6.67 %

For case 2  fish =   $\frac{3}{15} X100=20%$