For an investment with an interest rate compounded continuously, the formula would be
F = Pe^(rn), where r is the annual interest rate and n is the number of years.
F = 1050e^(0.055*5)
F = $1382.36
I hope I was able to answer your question.
Hello! The answer to your question would be as followed:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
-79-(7*w+3*(4*w-1)=0
-79 - (7w + 3 • (4w - 1)) = 0
Pulling out like terms :
Pull out like factors :
-19w - 76 = -19 • (w + 4)
-19 • (w + 4) = 0
Equations which are never true :
Solve : -19 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
Solve : w+4 = 0
Subtract 4 from both sides of the equation :
w = -4
w = -4
The annual rat of return for this investment would be
850000=650000*(1+(r/1))^(1*3)
I would guess the answer to be Tension, if not for the extra 'X'....
or
Extension, if you add another 'E'...
