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Ber [7]
2 years ago
10

For two weeks, Jonah recorded the daily temperature variations in three cities, each in a different geographical region of the c

ountry. In the table, he noted the mean daily temperature for each city, in degrees Fahrenheit, and the standard deviation (SD). Use the information in the table to select the true statement.
Stepford
Mean = 58
SD = 5
Angel Grove
Mean = 85
SD = 3
Bedrock
Mean = 72
SD = 2
1.Stepford is the least consistent in daily temperatures because its mean is the lowest.
2.Stepford is the least consistent in daily temperatures because its standard deviation is the highest.
3.Angel Grove is the least consistent in daily temperatures because its mean is the highest. 
4.Bedrock is the least consistent in daily temperatures because its standard deviation is the lowest.
Mathematics
2 answers:
Alona [7]2 years ago
8 0

Answer:

2. Stepford is the least consistent in daily temperatures because its standard deviation is the highest.

Step-by-step explanation:

Standard deviation is the average amount that each data point is from the mean.  The lower the standard deviation is, the closer each data point is to the mean; this means it is more consistent if it has a low standard deviation.

Stepford has the highest standard deviation; this means it is the most variable, or least consistent.

hjlf2 years ago
4 0

Answer:

Option 4

4.Bedrock is the least consistent in daily temperatures because its standard deviation is the lowest.

Step-by-step explanation:

For any sample, we have mean = sum of all readings/n i.e. average of all items in the sample.

Variance of a sample is a measurement of spread between the recorded numbers in a data set.  Variance is calculated by finding the differences between each number in the set and the mean, squaring the differences (to make them positive) and dividing the sum of the squares by the number of values in the set.   We square to make them positive, because negative effects should not nullify positive effects.

If spread between the numbers in the set and the mean is low, then automatically variance would be lower.

Of the three persons, Stepford, BedRock, and Angel Grove we find the variance is the least for Bed rock.

i.e. the spread in the sample of Bed rock from the mean is the least compared to others.

Hence consistent sample is that of Bedrock.



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Step-by-step explanation:

Let

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An article in Knee Surgery, Sports Traumatology, Arthroscopy, "Arthroscopic meniscal repair with an absorbable screw: results an
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Answer:

The mean number of successful surgeries is 1.57.

The variance of the number of successful surgeries is 0.3111.

Step-by-step explanation:

STEP 1

If the tear on the left knee has a rim width of less than 3mm, the probability that the surgery on the left knee will be successful (ls) is 0.90.

That isP(Is)=0.90

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The probability that the surgery on the left knee will fail (lf) is 0.10. That isP(V)=0.10

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If the tear on the right knee has a rim width of 3-6 mm, the probability that the surgery on the right knee will be successful (rs) is 0.67. That isP(rs)=0.67

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The probability that the surgery on the right knee will fail (rf) is 0.33.

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P(X = 0)=P(lf and rf)

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The number of successful surgeries is equal to 1 if the surgery on one knee is successful and the surgery on the other knee fails, that is

P(X =1)= P((ls and rf) or (if and rs))

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= (0.90)(0.33)+(0.10)(0.67)

= 0.364

The number of successful surgeries is equal to 2 if the surgeries on both knees are successful, that is

P(X = 2)=P(ls and rs)

= P(Is) P(rs)

=(0.90)(0.67)

= 0.603

So, the probability mass function of X is the following

X        0              1               2

f(x)     0.033      0.364      0.603

The mean number of successful surgeries is,

E(X)=∑xP(x)

=(0×0.033) +(1×0.364)+(2×0.603)

=1.57

the mean number of successful surgeries is 1.57

The expected value is obtained by taking the summation of the product of each possible value of the random variable X with its corresponding probabilities. Thus, the mean number of successful surgeries is 1.57.

STEP 2

The variance of the number of successful surgeries is,

Var(X)=∑x²P(x)-(E(x²)

=(0×0.033) + (1 × 0.364) +(2 × 0.603) - (1.57)²

= 2.776 -(1.57)²

=0.3111

The variance of the number of successful surgeries is 0.3111.

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