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2 years ago

7

A grocery store gives away a $10 gift card to every 25th customer and a $20 gift card to every 60th customer. Which customer wil

l be the first to receive both gift cards? Customer # b. After this customer receives both gift cards, what is the total amount in gift cards that the store has given away? $

1 answer:

Novosadov [1.4K]2 years ago

7 0

The 300th customer would be the first to recieve both. They would have given away 5 of the 20$ gift cards and 12 of the 10$ ones for a total of 17 gift cards.

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tatiyna

Answer:

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Step-by-step explanation:

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2 years ago

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In general, the probability that it rains on Saturday is 25%. If it rains on Saturday, the probability that it rains on Sunday i

lora16 [44]

Answer:

40%

Step-by-step explanation:

From the given statements:

The probability that it rains on Saturday is 25%.

P(Sunday)=25%=0.25

Given that it rains on Saturday, the probability that it rains on Sunday is 50%.

P(Sunday|Saturday)=50%=0.5

Given that it does not rain on Saturday, the probability that it rains on Sunday is 25%.

P(Sunday|No Rain on Saturday)=25%=0.25

We are to determine the probability that it rained on Saturday given that it rained on Sunday, P(Saturday|Sunday).

P(No rain on Saturday)=1-P(Saturday)=1-0.25=0.75

Using Bayes Theorem for conditional probability:

P(Saturday|Sunday)= $\frac{P(Sunday|Saturday)P(Saturday)}{P(Sunday|Saturday)P(Saturday)+P(Sunday|No Rain on Saturday)P(No Rain on Saturday)}$

= $\frac{0.5*0.25}{0.5*0.25+0.25*0.75}$

=0.4

There is a 40% probability that it rained on Saturday given that it rains on Sunday.

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2 years ago

You plan to work for 40 years and then retire using a 25-year annuity. You want to arrange a retirement income of $4000 per mont

Molodets [167]

Answer:

$311.74

Step-by-step explanation:

A financial calculator computes the payment amount to be $311.74.

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Your graphing calculator may have the capability to do this. Certainly, such calculators are available in spreadsheet programs and on the web.

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The appropriate formula is the one for the sum of terms of a geometric series.

Sn = a1·((1+r)^n -1)/(r) . . . . . where r is the monthly interest rate (0.005) and n is the number of payments (480). Filling in the given numbers, you have ...

$620827.46 = a1·(1.005^480 -1)/.005 = 1991.4907·a1

Then ...

$620827.46/1991.4907 = a1 ≈ $311.74

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2 years ago

Mrs. Adams deposited $12,000 into an account that earns an annual simple interest rate of 3.25%. She makes no other deposits or

lisabon 2012 [21]

Answer:

<em>Mrs. Adams will earn $3,120 of interest at the end of year 8.</em>

Step-by-step explanation:

<u>Simple Interest</u>

In simple interest, the money earns interest at a fixed rate, assuming no new money is coming in or out of the account.

We can calculate the interests earned by an investment of value A in a period of time t, at an interest rate r with the formula:

$I=A.r.t$

Mrs. Adams deposited an amount of A=$12,000 into an account that earns an annual simple interest rate of r=3.25%. We must find the interest earned in t=8 years. The interest rate is converted to decimal as:

$r=3.25/100=0.0325$

The interest is then calculated:

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Mrs. Adams will earn $3,120 of interest at the end of year 8.

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2 years ago

BRAINLIESTTT ASAP!! PLEASE HELP ME :)

Elanso [62]

Answer:

x=-2 (the actual solution)

x=-5 (the extraneous solution)

Step-by-step explanation:

First step is to isolate the radical part (the part with the square root).

So we will add 4 on both sides first:

$\sqrt{x+6}=x+4$

To get rid of square we are going to square both sides:

$x+6=(x+4)^2$

We are going to expand right hand side (you can use "F.O.I.L":

$x+6=x^2+4x+4x+16$

Subtract x on both sides and subtract 6 on both sides:

$0=x^2+4x+4x-x+16-6$

Combine like terms:

$0=x^2+7x+10$

We will now factor:

$0=(x+2)(x+5)$ (Since 2(5)=10 and 2+5=7)

Set both factors equal to 0:

x+2=0 or x+5=0

Solve first equation by subtracting 2 on both sides to obtain x=-2.

Solve second equation by subtracting 5 on both sides to obtain x=-5.

Now let's check to see if these are both actually indeed solutions to the equation we began with:

$\sqrt{x+6}-4=x$ for $x=-2$ :

$\sqrt{-2+6}-4=-2$

$\sqrt{4}-4=-2$

$2-4=-2$

$-2=-2$ is a true equation so $x=-2$ is indeed a solution.

$\sqrt{x+6}-4=x$ for $x=-5$ :

$\sqrt{-5+6}-4=-5$

$\sqrt{1}-4=-5$

$1-4=-5$

$-3=-5$ is false so $x=-5$ is what we call the extraneous solution.

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2 years ago

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