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2 years ago

The triangles shown below must be congruent.

Mathematics

2 answers:

n200080 [17]2 years ago

8 0

true by the angle side angle theorem

Alik [6]2 years ago

3 0

Answer:

Option A is correct.

Yes, it is true that the triangles shown are congruent.

Step-by-step explanation:

Labelled the diagram as shown below in the attachment:

In triangle ABC and triangle PQR

$\angle ABC \cong \angle PQR = 90^{\circ}$ [Angle]

$\angle ACB \cong \angle QPR = 40^{\circ}$ [Angle]

$AC \cong PR = 12$ units [Side]

AAS(Angle-Angle-Side) postulates states that the two angles and the non- included side of one triangle are congruent to the two angles and the non-included side of the other triangle., then the triangles are congruent.

Then, by AAS

$\triangle ABC \cong \triangle PQR$

Therefore, the given triangles shown must be congruent.

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Answer:

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Step-by-step explanation:

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2 years ago

jack puts 1/3 pound of birdseed into his feeder every time he fills it. how many can jack fill his bird feeder with 4 pounds of

Flura [38]

Answer: Jack can fill his feeder 12 times with 4 pounds of birdseed.

Step-by-step explanation:

You need to analize the information given in the exercise, You know that every time Jack fills the feeder, he put $\frac{1}{3}$ pounds into it.

Then, in order to solve this exercise, let "x" represents the number of times that Jack can fill his feeder with 4 pounds of birdseed.

Keeping on mind the data provided in the exercise, you can set up de following proportion:

$\frac{1}{\frac{1}{3}} = \frac{x}{4}$

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2 years ago

A segment has endpoints A (-1, 1) and B (8, 4) . If the segment is divided into four equal parts, the coordinates of the point c

riadik2000 [5.3K]

Line is divided into 4 equal parts.

we have to find a point which is closest to point A.

So that means required point P(x,y) is at 1 unit away from A(-1,1) and 3 unit away from B(8,4)

Now we just need to use section formula to get the coordinate of required point using m1=1 and m2=3

$\left ( \frac{m_1x_2+m_2x_1}{m_1+m_2} , \frac{m_1y_2+m_2y_1}{m_1+m_2} \right )$

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$= \left ( \frac{8-3}{4} , \frac{4+3}{4} \right )$

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So the final answer is $\left ( \frac{5}{4} , \frac{7}{4} \right )$ .

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2 years ago

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Answer:

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<span>AB is parallel to A'B'.

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