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Mekhanik [1.2K]
2 years ago
6

Need help

Mathematics
1 answer:
kow [346]2 years ago
3 0

1)\\\\\dfrac{-45}{-5}=45:5=9


2)\\(-2)(4)=-8\\(2)(-4)+-8\\-16:2=-8\\-16:(-2)=8\neq-8\\\\\text{All of the following expressions have the same value except}\ -16:-2.


3)\\-3^2=-3\cdot3=-9


(-2)^4=(-2)(-2)(-2)(-2)=16\\-2^4=-(2)(2)(2)(2)=-16\neq16\\(-2)(-2)(-2)(-2)=16\\2^4=(2)(2)(2)(2)=16\\\\\text{All of the following are equivalent except}\ -2^4.

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Apply the distributive property to factor out the greatest common factor 16g+20h
UkoKoshka [18]

Answer:

4(4g+5h)

Step-by-step explanation:

Factor out the 4.

5 0
2 years ago
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6 0
2 years ago
Read 2 more answers
Suppose that the probability density function for the length x in feet of some type of fish caught by sport fishermen is given b
Firdavs [7]

Answer:

The probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is 0.4375.

Step-by-step explanation:

The probability density function or p.d.f. for the length <em>x,</em> in feet, of some type of fish caught by sport fishermen is :

p(x) = \left \{{{(\frac{1}{4})\ ;\  0\leq x\leq 4 } \atop{0\ ;\ otherwise} \right.

The probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is:

P(0.25\leq X\leq 2)=\int\limits^{0.25}_{2} {(\frac{1}{4})} \, dx \\=|(\frac{1}{4})x|^{2}_{0.25}\\=(\frac{1}{4})(2-0.25)\\=0.4375

Thus, the probability that a fish caught by a fisherman is between 0.25 feet and 2 feet long is 0.4375.

8 0
2 years ago
Find the integer a such that<br> a.a ≡ 43 (mod 23) and −22 ≤ a ≤ 0.
Margaret [11]
Given that a is an integer from -22 to 0 such that a is equivalent to 43 (mod 23).

Such a can be obtained as follows:

a = 43 (mod 23) - 23 = 20 - 23 = -3.

Therefore, a = -3.
8 0
2 years ago
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