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choli [55]
2 years ago
4

If c(x) = 4x – 2 and d(x) = x2 + 5x, what is (c*d)(x)?

Mathematics
2 answers:
Aneli [31]2 years ago
8 0
C(x)=4x-2       and d(x)=x^{2} +5x
(c*d)(x)
(4x-2)(x^{2} +5x)
Open the brackets and multiply the terms in the order shown below;
4x(x^{2} +5x)-2(x^{2} +5x)
=4x^{3} +20 x^{2} -2 x^{2} -10x
=4x^{3} +18 x^{2} -10x
ser-zykov [4K]2 years ago
6 0

Answer:

The answer is A.

Step-by-step explanation:

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The grocery store is having a sale on frozen vegetables. 4 bags are being sold for $11.96. At this rate what is the cost of: 9 b
Alexandra [31]

Answer:

$26.91

Step-by-step explanation:

11.96 divided 4 = 2.99

2.99 x 9 = $26.91

4 0
2 years ago
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An equilateral triangle has a semiperimeter of 6 meters.
guapka [62]

Answer:

7

Step-by-step explanation:

An equilateral triangle has a semiperimeter of 6 meters.

Heron’s formula: Area = StartRoot s (s minus a) (s minus b) (s minus c) EndRoot

An equilateral triangle has a semiperimeter of 6 meters. What is the area of the triangle? Round to the nearest square meter.

2 square meters

7 square meters

20 square meters

78 square meters

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2 years ago
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What is the measure of Angle J K L? Triangle J K L . The exterior angle to angle K has a measure of 83 degrees. 83 degrees 97 de
nasty-shy [4]

Answer:

The measure of angle JKL is 97 degrees.

Step-by-step explanation:

Given:

A triangle JKL .

Measure of exterior angle K = 83 degrees

We have to find the measure of \angle JKL .

In (\triangle\ JKL) we see that the exterior angle is in linear pair with \angle JKL .

Note:

Linear pair angles sum is 180 degree.

Let \angle JKL be 'x' degrees .

So,

⇒ x+83=180

⇒ <em>Subtracting 83 from both sides.</em>

⇒ x+83-83=180-83

⇒ x=180-83

⇒ x=97 degrees

The measure of angle JKL in the triangle is of 97 degrees.

5 0
2 years ago
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An exterior angle of an isosceles triangle has measure 130°. Find two possible sets of measures for the angles of the triangle.
frozen [14]
(1) it can be both exterior of vertex or base. 180-130=50°
vertex is 50°:     base=(180-50)/2=65°
base is 50°:       vertex= 180-2*50=80°

vertex 50 base 65; vertex 80, base 50

(2)base=180-130=50°
vertex=180-2*50=80°

base 50 vertex 80
5 0
2 years ago
Which shows one way to determine the factors of 12x3 – 2x2 + 18x – 3 by grouping?
AleksAgata [21]

we are given

12x^3-2x^2+18x-3

Firstly, we will split terms

2x^2*6x-1*2x^2+3*6x-1*3

We can group first two and last two terms

(2x^2*6x-1*2x^2)+(3*6x-1*3)

we can see that 2x^2 is common in first two terms

and 3 is common in last two terms

so, we can factor factor out 2x^2 from first group and 3 from second group

we get

=2x^2(6x-1)+3(6x-1)

we can see that each terms are multiple of 6x-1

so, we can factor out 6x-1

so, we get

12x^3-2x^2+18x-3 =(2x^2+3)(6x-1)............Answer


4 0
2 years ago
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