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Norma-Jean [14]
2 years ago
12

the daily production cost, c, for x units is modeled by the equation: c = 200 – 7x 0.345x2 explain how to find the domain and ra

nge of c.
Mathematics
2 answers:
sattari [20]2 years ago
7 0

This is a quadratic function, which is usually defined on all reals. But, the domain is restricted to  x≥0 because it does not make sense to produce a negative number of units.


Find the vertex of the parabola at

(10.14, 164.5).


Since the parabola opens up, the range is y ≥ 164.5


jenyasd209 [6]2 years ago
6 0
C(x) = 200 - 7x + 0.345x^2

Domain is the set of x-values (i.e. units produced) that are feasible. This is all the positive integer values + 0, in case that you only consider that can produce whole units.

Range is the set of possible results for c(x), i.e. possible costs.

You can derive this from the fact that c(x) is a parabole and you can draw it, for which you can find the vertex of the parabola, the roots, the y-intercept, the shape (it open upwards given that the cofficient of x^2 is positive). Also limit the costs to be positive.

You can substitute some values for x to help you, for example:

x      y
0    200
1    200 -7 +0.345 = 193.345
2    200 - 14 + .345 (4) = 187.38
3    200 - 21 + .345(9) = 182.105
4    200 - 28 + .345(16) = 177.52
5    200 - 35 + 0.345(25) = 173.625
6    200 - 42 + 0.345(36) = 170.42

10  200 - 70 + 0.345(100) =164.5
11 200 - 77 + 0.345(121) = 164.745
 
 
The functions does not have real roots, then the costs never decrease to 0.

The function starts at c(x) = 200, decreases until the vertex, (x =10, c=164.5) and starts to increase.

Then the range goes to 164.5 to infinity, limited to the solutcion for x = positive integers.

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The roof of a house seen from the front is an isosceles triangle \Delta ABC ΔABC with base 14.5 m and sides of length 8.5 m. Fin
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Answer:

4.4 m

Step-by-step explanation:

Draw the height of the triangle (perpendicular line from point A to line BC).  Since ABC is an isosceles triangle, the height is a perpendicular bisector, so it splits the triangle into two congruent right triangles.

Use Pythagorean theorem to find the height.

c² = a² + b²

(8.5 m)² = (14.5/2 m)² + h²

h ≈ 4.4 m

7 0
2 years ago
Erica can run 1 6 6 1 ​ start fraction, 1, divided by, 6, end fraction of a kilometer in a minute. Her school is 3 4 4 3 ​ start
Brut [27]

Her school is 2/3 miles away

2/3=4/6miles

So we need to find out how long it will take for her to run home from school...

School=4/6 miles

In 1 minutes she can run 1/6 miles

1min=1/6miles

In 2 minutes she can run 1/6+1/6 miles (1/6+1/6=2/6)

2min=2/6miles

3min=3/6miles

4min=4/6miles

It will take Erica 4 minutes to run 4/6 miles, so it'll take her 4 minutes to get home.

8 0
2 years ago
Two boats leave port at noon. Boat 1 sails due east at 12 knots. Boat 2 sails due south at 8 knots. At 2 pm the wind diminishes
Ivan

Answer:

14.86 knots.

Step-by-step explanation:

<em>Given that:</em>

The boats leave the port at noon.

Speed of boat 1 = 12 knots due east

Speed of boat 2 = 8 knots due south

At 2 pm:

Distance traveled by boat 1 = 24 units due east

Distance traveled by boat 2 = 16 units due south

Now, speed of boat 1 changes to 9 knots:

At 3 pm:

Distance traveled by boat 1 = 24 + 9= 33 units due east

Distance traveled by boat 2 = 16+8 = 24 units due south

Now, speed of boat 1 changes to 8+7 = 15 knots

At 5 pm:

Distance traveled by boat 1 = 33 + 2\times 9= 51 units due east

Distance traveled by boat 2 = 24 + 2 \times 15 = 54 units due south

Now, the situation of distance traveled can be seen by the attached right angled \triangle AOB.

O is the port and A is the location of boat 1

B is the location of boat 2.

Using pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow AB^{2} = OA^{2} + OB^{2}\\\Rightarrow AB^{2} = 51^{2} + 54^{2}\\\Rightarrow AB^{2} = 2601+ 2916 = 5517\\\Rightarrow AB = 74.28\ units

so, the total distance between the two boats is 74.28 units.

Change in distance per hour = \dfrac{Total\ distance}{Total\ time}

\Rightarrow \dfrac{74.28}{5} = 14.86\ knots

6 0
2 years ago
5.1x10^-1 as an ordinary number?
scZoUnD [109]
=0.51=51/100............
8 0
2 years ago
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