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AVprozaik [17]
2 years ago
10

A package of pencils cost $6.25 per set at an office supply store. Which equation can be used to determine the price, P, of n se

ts of these pencils? n = 6.25P P = 6.25n n equals 6.25 over P P equals 6.25 over n
Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
6 0

Answer:

<h2>P = 6.25n</h2>

Step-by-step explanation:

The problem says that each set costs $6.25, and <em>n </em>refers to sets of pencils.

So, we know that "per" refers to multiplication, because if each set of pencil costs $6.25, then a <em>n </em>quantity of pencils will be the sum of $6.25 <em>n </em>times, which is the definition of multiplication. So, the equation that correctly determined the price is:

P=6.25n

The price is $6.25 per set of pencils, that is what this equation says.

Therefore, the right answer is the second one.

ladessa [460]2 years ago
5 0

To solve, it would be 6.25n. That eliminates both 6n25 over P, P equals 6.25 over n, and n=6.25P, leaving P=6.25n as the answer.

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The 3rd degree Taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − (x − π/2) + 1/6 (x − π/2)3 + R3(x). Usin
Otrada [13]

Answer:

The cosine of 86º is approximately 0.06976.

Step-by-step explanation:

The third degree Taylor polynomial for the cosine function centered at a = \frac{\pi}{2} is:

\cos x \approx -\left(x-\frac{\pi}{2} \right)+\frac{1}{6}\cdot \left(x-\frac{\pi}{2} \right)^{3}

The value of 86º in radians is:

86^{\circ} = \frac{86^{\circ}}{180^{\circ}}\times \pi

86^{\circ} = \frac{43}{90}\pi\,rad

Then, the cosine of 86º is:

\cos 86^{\circ} \approx -\left(\frac{43}{90}\pi-\frac{\pi}{2}\right)+\frac{1}{6}\cdot \left(\frac{43}{90}\pi-\frac{\pi}{2}\right)^{3}

\cos 86^{\circ} \approx 0.06976

The cosine of 86º is approximately 0.06976.

8 0
2 years ago
A science test, which is worth 100 points, consists of 24 questions. Each question is worth either 3 points or 5 points. If x is
anzhelika [568]
You need to solve for one variable in equation 1 and substitute it in equation 2 to solve.

Equation 1: x+y=24
x= number of 3 pt questions
y= number of 5 pt questions
24= Total number of questions

Equation 2: 3x+5y=100
100= Total point value possible on test
3x= point value of 3 pt questions
5y= point value of 5 pt questions

x+y=24
Subtract y from both sides
x=24-y

Substitute in equation 2:
3x+5y=100
3(24-y) +5y=100
72-3y+5y=100
72+2y=100
Subtract 72 from both sides
2y=28
Divide both sides by 2
y=14

Substitute y=14 back in to solve for x:
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Subtract 70 from both sides
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So there are 10 three point questions
There are 14 five point questions.

Hope this helped! :)
6 0
2 years ago
Read 2 more answers
A company manufactures aluminum mailboxes in the shape of a box with a half-cylinder top. The company will make 1863 mailboxes t
worty [1.4K]

Answer:

3433 m²

Step-by-step explanation:

From the image, we have a rectangular box without cover and half a cylinder on top.

Formula for surface area of rectangular box with top is;

S = 2(lh + wh + lw)

From the image,

l = 0.6 m

w = 0.4 m

h = 0.55 m

Thus;

S = 2((0.6 × 0.55) + (0.4 × 0.55) + (0.6 × 0.4))

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Now, since the top is not included for this figure, then;

Surface area of this rectangular box is;

S1 = 1.58 - (lw) = 1.58 - (0.4 × 0.6) = 1.34 m²

Surface area of a cylinder is;

S = 2πr² + 2πrh

r is radius and in this case = 0.4/2 = 0.2 m

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S = 2π(0.2² + (0.2 × 0.6))

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Since it is half cylinder, then we have;

S2 = 1.005/2

S2 = 0.5025 m²

Total surface area; S_t = S1 + S2

S_t = 1.34 + 0.5025

S_t = 1.8425 m²

This is the surface area of one mail box.

Thus, for 1863 mailboxes, total surface area is;

S = 1863 × 1.8425 = 3432.5775 m²

Approximating to the nearest Sq.m gives;

S = 3433 m²

6 0
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lorasvet [3.4K]

Answer:

A. 180

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