Answer:
True options: 1, 2 and 5
Step-by-step explanation:
From the given diagram, you can see that the center of the hyperbola is placed at the origin, so first option is true (see attached diagram for definition of center, vertices, foci, i.e.)
There are two vertices of the hyperbola, they are placed at (-6,0) and (6,0), so second option is true.
The transverse axis is the segment connecting vertices, this segment is horizontal, so option 3 is false.
The foci are not placed within the rectangular reference box, so this option is false.
The directrices are vertical lines with equations 
, so this option is true.
The Venn Diagram that represents the problem is shown below
P(E|F) and P(F|E) are the conditional probability.
P(E|F) is given by P(E∩F) ÷ P(F) = ¹/₂ ÷ ¹/₂ = 1
P(F|E) is given by P(F∩E) ÷ P(E) = ¹/₂ ÷ ¹/₂ = 1
The formula for determining the distance of the focus from the vertex is as follows,
f = x² / 4a
where f is focus, x is the radius (half the value of diameter), and a is the depth. Substituting the known values to the given equation,
f = (30/2 mm)² / (4)(5 mm)
f = 11.25 mm
<em>ANSWER: 11.25 mm</em>
The answer
f(x) = 0.7(6)x = <span>f(x) = 0.7(6)^x, and </span><span>g(x) = 0.7(6)–x= </span>g(x) = 0.7(6)^-x=1/<span>0.7(6)^x
so </span>
g(x) =1/<span>0.7(6)^x=1 /</span><span><span>f(x)
</span> the relationship between f and g are </span>g(x) =1 /<span>f(x) or </span><span>g(x) . <span>f(x) = 1</span> </span>
Answer:
3. Standard deviation is the square root of the variance.
4. Standard deviation is useful because it has the same units as the underlying data.
Step-by-step explanation:
3. In statistics, the dispersion in a given data with respect to its mean distribution can be determined or measured by standard deviation and variance. The standard deviation of a distribution can also be determined as the square root of variance.
4. Standard deviation is measured in the same units as that of the original data. Thus it has the same units as the underlying data.
