Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

2 answers:

8 0

Answer by JKismyhusbandbae: So to find the pattern we can subtract 49 and 42 to get 7 which should be our pattern to double check add 49 plus 7 to get 56 so 56 plus 7 equals 63.

pychu [463]2 years ago

8 0

1. Betty collected 42 petition signatures on the first day, 49 on the second day, and 56 on the third day. If this pattern continues, how many signatures will she collect on the fourth day? Explain how you obtained your answer.

The pattern is getting 7 more signatures everyday.

56 + 7 = 63

I found this answer by finding the rule and adding it to the third day to get the total amount of signatures for the fourth day.

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a rectangular piece of paper 71 cm long and 10m wide . a cylinder is formed by rolling the paper along its length , find volume

natka813 [3]

Answer:

Volume=355 cm³

Step-by-step explanation:

I assume it should be 10 cm, not 10 m. If it is 10 m, everything will have to be adjusted.

Circumference = 2 $\pi$ r

10=2 $\pi$ r

10÷2 $\pi$ =r

1.59=r

V= $\pi$ r²h

V= $\pi$ (1.59)(71)

v=355

7 0

2 years ago

charmaine and tesha each have a number of cards, in the ratio 2:3. tesha and holly have a number of cards in the ratio 2:1. if t

Sav [38]

C:t=2:3
t:h=2:1

multiply first equation by 2 and 2nd by 3
c:t=4:6
t:h=6:3
so
c:t:h=4:6:3

if t is 4 more than c
t is 6 units and c is 4
6-4=2
so 4=2 units
2=1 unit

hollly is 3 units
3*2=6
holly has 6 cards

3 0

2 years ago

A normal distribution curve, where x = 70 and σ = 15, was created by a teacher using her students’ grades. What information abou

mash [69]

Answer:

The median and mode of the students grade is 70.

Most of the students scored between 40 and 100.

Step-by-step explanation:

From the provided information it can be seen that the mean of the distribution is, μ = 70 and the standard deviation is, σ = 15.

For a Normal distributed data the mean, median and mode are the same.

So, the median and mode of the students grade is 70.

The standard deviation of the data represents the spread of the observation, i.e. how dispersed the values are along the curve.

In statistics, the 68–95–99.7 rule, also recognized as the empirical rule, is a shortcut used to recall that 68.27%, 95.45% and 99.73% of the values of a Normally distributed data lie within one, two and three standard deviations of the mean, respectively.

$P(\mu-\sigma$