Question

An office uses paper drinking cups in the shape of a cone, with dimensions as shown. To the nearest tenth of a cubic inch, what is the volume of each drinking cup?

Answer 1

The volume of a cone is given by the formula $V=\frac{1}{3} \pi r^{2} h$

If we plug in the known information into the formula, we will get the answer.

$d=2.75 in$

We know radius is half of d, so $r=0.5*2.75=1.375 in$

The height is given as 4 in.

Pluggin all of these in the original formula gives us:

$V=\frac{1}{3} \pi (1.375)^{2} (4)=7.919 cubic inches$

Rounded to the nearest tenth, our final answer is:

V=7.9 cubic inches

Answer 2

ANSWER

$Volume\approx 7.90 in^3$

to the nearest tenth

EXPLANATION

The given cup has the shape of a cone with dimension,

$height=4in.$

and

$diameter=2\frac{3}{4}in.$

The formula for calculating the area of a cone is given by;

$Volume=\frac{1}{3} \pi r^2h.$

Where r is the radius of the circular base.

We therefore divide the diameter in to two to find the radius.

This implies that,

$r=2\frac{3}{4} \div2$

$r=\frac{11}{4} \div2$

$r=\frac{11}{4} \times \frac{1}{2}$

$r=\frac{11}{8}$

We now plug in all the above in to the formula, to get,

$Volume=\frac{1}{3} \pi (\frac{11}{8})^2\times4$

$Volume=\frac{121}{48} \pi$

$Volume=7.918$

$Volume\approx 7.90 in^3$

to the nearest tenth