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forsale [732]
1 year ago
7

the graph plots four equations, a, b, c, and d: line a joins ordered pair negative 6, 16 and 9, negative 4. line b joins ordered

pair negative 2, 20 and 8, 0. line c joins ordered pair negative 7, negative 6 and 6, 20. line d joins ordered pair 7, 20 and 0, negative 7. which pair of equations has (4, 8) as its solution? equation a and equation c equation b and equation c equation c and equation d equation b and equation d
Mathematics
2 answers:
fomenos1 year ago
6 0
The pair of equations that has (4, 8) as its solution are the two equations represented by the lines which intersect at point (4, 8). The lines are line b and line d.
Therefore the equations are equation b and equation a.
IRISSAK [1]1 year ago
4 0

Answer with explanation:

Eqation of line joining two points (a,b) and (c,d) is given by

       \rightarrow \frac{y-b}{x-a}=\frac{b-d}{a-c}

Eqation of line a, which joins two points (-6,16) and (9,-4) is

          \rightarrow \frac{y-16}{x+6}=\frac{16-(-4)}{-6-9}\\\\\rightarrow -15 y+240=20 x+120\\\\20x+15y=120\\\\4x+3y=24

⇒Putting, x=4 and , y=8 in above equation

   4 × 4+3×8=16+24=40≠24

Point (4,8) does not lie on this line.

⇒⇒Eqation of line b, which joins two points (2,20) and (8,0) is

       \rightarrow \frac{y-20}{x-2}=\frac{20-0}{2-8}\\\\\rightarrow -6 y+120=20 x-40\\\\20x+6y=160\\\\10x+3y=80

⇒Putting, x=4 and , y=8 in above equation

   10 × 4+3×8=40+24=64≠80

Point (4,8) does not lie on this line.

⇒⇒Eqation of line c, which joins two points (7,-6) and (6,20) is

       \rightarrow \frac{y-20}{x-6}=\frac{20-(-6)}{6-7}\\\\\rightarrow -y+20=26 x-156\\\\26x+6y=176\\\\13x+3y=88

⇒Putting, x=4 and , y=8 in above equation

   13× 4+3×8=52+24=76≠88

Point (4,8) does not lie on this line.

⇒⇒Eqation of line d, which joins two points (7,20) and (0,-7) is

       \rightarrow \frac{y-20}{x-7}=\frac{20-(-7)}{7-0}\\\\\rightarrow 7y-140=27x-189\\\\27x-7y=189-140\\\\27x-7y=49

  ⇒Putting, x=4 and , y=8 in above equation

   27× 4-7×8=108-56=52≠24

Point (4,8) does not lie on this line.

⇒None of the two lines has point of Intersection at point (4,8).

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  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

  • The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

To determine:

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

where

  • Principle = P
  • Annual rate = r
  • Compound = n
  • Time  = (t in years)
  • A = Total amount

Given:

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

To determine:

Total amount = A = ?

so using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

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