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forsale [732]
2 years ago
7

the graph plots four equations, a, b, c, and d: line a joins ordered pair negative 6, 16 and 9, negative 4. line b joins ordered

pair negative 2, 20 and 8, 0. line c joins ordered pair negative 7, negative 6 and 6, 20. line d joins ordered pair 7, 20 and 0, negative 7. which pair of equations has (4, 8) as its solution? equation a and equation c equation b and equation c equation c and equation d equation b and equation d
Mathematics
2 answers:
fomenos2 years ago
6 0
The pair of equations that has (4, 8) as its solution are the two equations represented by the lines which intersect at point (4, 8). The lines are line b and line d.
Therefore the equations are equation b and equation a.
IRISSAK [1]2 years ago
4 0

Answer with explanation:

Eqation of line joining two points (a,b) and (c,d) is given by

       \rightarrow \frac{y-b}{x-a}=\frac{b-d}{a-c}

Eqation of line a, which joins two points (-6,16) and (9,-4) is

          \rightarrow \frac{y-16}{x+6}=\frac{16-(-4)}{-6-9}\\\\\rightarrow -15 y+240=20 x+120\\\\20x+15y=120\\\\4x+3y=24

⇒Putting, x=4 and , y=8 in above equation

   4 × 4+3×8=16+24=40≠24

Point (4,8) does not lie on this line.

⇒⇒Eqation of line b, which joins two points (2,20) and (8,0) is

       \rightarrow \frac{y-20}{x-2}=\frac{20-0}{2-8}\\\\\rightarrow -6 y+120=20 x-40\\\\20x+6y=160\\\\10x+3y=80

⇒Putting, x=4 and , y=8 in above equation

   10 × 4+3×8=40+24=64≠80

Point (4,8) does not lie on this line.

⇒⇒Eqation of line c, which joins two points (7,-6) and (6,20) is

       \rightarrow \frac{y-20}{x-6}=\frac{20-(-6)}{6-7}\\\\\rightarrow -y+20=26 x-156\\\\26x+6y=176\\\\13x+3y=88

⇒Putting, x=4 and , y=8 in above equation

   13× 4+3×8=52+24=76≠88

Point (4,8) does not lie on this line.

⇒⇒Eqation of line d, which joins two points (7,20) and (0,-7) is

       \rightarrow \frac{y-20}{x-7}=\frac{20-(-7)}{7-0}\\\\\rightarrow 7y-140=27x-189\\\\27x-7y=189-140\\\\27x-7y=49

  ⇒Putting, x=4 and , y=8 in above equation

   27× 4-7×8=108-56=52≠24

Point (4,8) does not lie on this line.

⇒None of the two lines has point of Intersection at point (4,8).

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miv72 [106K]

Answer:

For this case since since they not want to differentiate between the campuses, so is good to use a simple random sampling or SRS, that is a procedure in order to select a sample of size n from a population of size N known, and each element of the population have the sample probability of being selected p=\frac{1}{N}

So then the administrator can select a random sample of n students from all the campuses from the CSU University and obtain the distance from hometwon to campuses for the selected sample and then calculate the average and use this to inference.

Other possibility is use a systematic random sampling for example they can define a random number k and they can select 1 student each k individuals and then create a random sample of size n and calculate the average for this in order to do inference.

The convenience sampling is not too useful since is not a probabilistic method.

Step-by-step explanation:

For this case we can clasify this study as an enumerative study and inferential since they want to identify the average distance between the hometowns of students and their campuses.

For this case the sampling frame represent all the 23 campuses, and is known for the researcher,

For this case since since they not want to differentiate between the campuses, so is good to use a simple random sampling or SRS, that is a procedure in order to select a sample of size n from a population of size N known, and each element of the population have the sample probability of being selected p=\frac{1}{N}

So then the administrator can select a random sample of n students from all the campuses from the CSU University and obtain the distance from hometwon to campuses for the selected sample and then calculate the average and use this to inference.

Other possibility is use a systematic random sampling for example they can define a random number k and they can select 1 student each k individuals and then create a random sample of size n and calculate the average for this in order to do inference.

The convenience sampling is not too useful since is not a probabilistic method.

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GarryVolchara [31]
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leonid [27]

Answer:

Step-by-step explanation:

Given triangles are similar, so we setup a proportion  

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7 0
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