Answer: PLEASE GIVE BRAINLIEST
72 integers
Step-by-step explanation:
Starting From 82-174 every integer is included in T so every integer that is not included in T but included in R would be 82-10 so every integer from 10 to 82.
Question:
Read the excerpt from Julius Caesar, act 1, scene 2.
CASSIUS: ‘Tis just; And it is very much lamented, Brutus, That you have no such mirrors as will turn Your hidden worthiness into your eye, That you might see your shadow. I have heard 5 Where many of the best respect in Rome– Except immortal Caesar‐speaking of Brutus, And groaning underneath this age’s yoke, Have wished that noble Brutus had his eyes.
BRUTUS: Into what dangers would you lead me, Cassius, 10 That you would have me seek into myself For that which is not in me?
CASSIUS: Therefore, good Brutus, be prepared to hear. And since you know you cannot see yourself So well as by reflection, I, your glass, 15 Will modestly discover to yourself That of yourself which you yet know not of.
Answer:
The correct choice is D)
Explanation:
Cassius speaks of Brutus as one who is unable to see or know his own value and presumes to help him therewith. He does this by pointing out that many of the well respected people in Rome wish that he were in Caesars shoes as King.
Cheers!
Answer:
The Answer is: The first number is -70 and the second number is -68.
Step-by-step explanation:
Let f = first number and s = second number.
The sum of both is -138:
f + s = -138
The difference is -2
f - s = -2
Solve for f:
f = -2 + s
f = s - 2
Substitute:
s - 2 + s = -138
2s = -136
s = -68, the second number
Solve for f:
f = s - 2
f = -68 - 2 = -70, the first number
Proof:
f + s = -138
-68 + (-70) = -138
-138 = -138
Then:
f - s = -2
-70 - (-68) = -2
-70 + 68 = -2
-2 = -2
Hope this helps! Have an Awesome Day!! :-)
Answer:
dy/dx = -1/√(1 - x²)
For 0 < y < π
Step-by-step explanation:
Given the function cos y = x
-siny dy = dx
-siny dy/dx = 1
dy/dx = -1/siny (equation 1)
But cos²y + sin²y = 1
=> sin²y = 1 - cos²y
=> siny = √(1 - cos²y) (equation 2)
Again, we know that
cosy = x
=> cos²y = x² (equation 3)
Using (equation 3) in (equation 2), we have
siny = √(1 - x²) (equation 4)
Finally, using (equation 4) in (equation 1), we have
dy/dx = -1/√(1 - x²)
The largest interval is when
√(1 - x²) = 0
=> 1 - x² = 0
=> x² = 1
=> x = ±1
So, the interval is
-1 < x < 1
arccos(1) < y < arxcos(-1)
= 0 < y < π