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elena55 [62]
2 years ago
8

4. Suppose a copy machine is set to reduce a picture that's 8.5 inches by 11 inches to picture dimensions one-half the original

size. What proportion shows this reduction? A. 8.5⁄11 = 5.5⁄4.25 B. 8.5⁄11 = 17⁄22 C. 8.5⁄11 = 2.125⁄2.75 D. 8.5⁄11 = 4.25⁄5.5
Mathematics
2 answers:
egoroff_w [7]2 years ago
6 0

B. because so what u need to do is.....

8.5÷11=  0.77272... so then you try the other side which is

17÷22= 0.77272... and so your answer will be

                                         B. 8.5/11 = 17/22



Yuri [45]2 years ago
5 0

so the 8.5/11 will be reduced by half.

half of 8.5 is 4.25.

half of 11 is 5.5............................\bf \stackrel{original}{\cfrac{8.5}{11}}=\stackrel{reduction}{\cfrac{4.25}{5.5}}

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If a 5 foot post casts an 8 foot shadow at the same time that a nearby tree casts a 48 foot shadow how tall is the tree
andriy [413]
The first thing we are going to assume for this case is that the tree and the post are located in the same place.
 From that place, both cast a shadow in the same direction.
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the tree is 30 feet tall
3 0
2 years ago
you accidentally dropped a coin from the top of 10 stairs. what is the probability that it will land on the 4th step facing up
Roman55 [17]

Answer:

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3 0
2 years ago
. According to Management Accounting, salary figures for certified management accountants (CMAs) who are in the field less than
Mice21 [21]

Answer:

The Mean is not equal to $31,129.

Step-by-step explanation:

Consider the provided information.

The mean is $31129

Thus, the null hypothesis H_0: \mu = 31129

Alternative hypothesis H_a: \mu \neq 31129

A random sample of 15 firstyear CMAs in Denver produces a mean salary of $32,279, with a standard deviation of $1,797.

Thus the value mean of sample is 32279, standard deviation is 1797 and number of samples are 15.

Now use the 2 sided t-test.

t=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

Now substitute the respective values in the above formula.

t=\frac{32279-31129}{\frac{1797}{\sqrt{15}}}

t=\frac{1150}{464}

Test Value = 2.4785  approximately

Now, find the corresponding p-value in your t-table with DF(degree of freedom) 14.

p = 0.0265  

as the value of  p < 0.05, so you reject null hypothesis.  

Thus, the Mean is not equal to $31,129.

7 0
2 years ago
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