Answer:
The first pizza is 6 slices, so each slice is 1/6 of a pizza. The second pizza is 4 slices, so each slice is 1/4 of a pizza. If you were to take one slice of each, you would get 1/6 +1/4 slice, which would be 5/12 of a pizza, as opposed to if you took 2 slices of the first pizza, which would only be 4/12 of a pizza.
<span><span>-2-2 + 2 = 0(-2, 0)</span><span>-1-1 + 2 = 1(-1, 1)</span><span>00 + 2 = 2(0, 2)</span><span>11 + 2 = 3(1, 3)</span><span>22 + 2 = 4<span>(2, 4)</span></span></span>
A score of 85 would be 1 standard deviation from the mean, 74. Using the 68-95-99.7 rule, we know that 68% of normally distributed data falls within 1 standard deviation of the mean. This means that 100%-68% = 32% of the data is either higher or lower. 32/2 = 16% of the data will be higher than 1 standard deviation from the mean and 16% of the data will be lower than 1 standard deviation from the mean. This means that 16% of the graduating seniors should have a score above 85%.
Let's convert the task into an example, simplifyng which will make us able to get the answer.
So, according to the task:
![\sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} * \sqrt[9]{x} = \sqrt[1/ 9 ]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x} * \sqrt[1/9]{x}](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B9%5D%7Bx%7D%20%0A%0A%3D%20%20%20%5Csqrt%5B1%2F%209%20%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2A%20%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20)
Now we can simplify:
![\sqrt[1/9]{x} + 1/9+1/9+1/9 = x^{4/9}](https://tex.z-dn.net/?f=%20%5Csqrt%5B1%2F9%5D%7Bx%7D%20%2B%201%2F9%2B1%2F9%2B1%2F9%0A%0A%3D%20x%5E%7B4%2F9%7D%20)
So the answer is <span>
C:x to the four ninths power</span>
Answer:
Step-by-step explanation:
Move the decimal point in the divisor and dividend.
Turn the divisor (the number you’re dividing by) into a whole number by moving the decimal point all the way to the right. At the same time, move the decimal point in the dividend (the number you’re dividing) the same number of places to the right.
Place a decimal point in the quotient (the answer) directly above where the decimal point now appears in the dividend.
Divide as usual, being careful to line up the quotient properly so that the decimal point falls into place.
Line up each digit in the quotient just over the last digit in the dividend used in that cycle.
