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Pachacha [2.7K]
1 year ago
12

Evan takes 100 milligrams of medicine. The amount of medicine in his bloodstream decreases by 0.4 milligram each minute for a nu

mber of minutes, m, after that. He writes the expression 100 – 0.4m to find the amount of medicine in his bloodstream after m minutes. Which statement about his expression is true?
Mathematics
2 answers:
jolli1 [7]1 year ago
7 0

Answer:

b      It is the difference between the initial amount and the amount of decrease after m minutes.

Step-by-step explanation:


faltersainse [42]1 year ago
5 0

the whole statement is true, make sure you read all of your choices next time and list them below.

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I am choosing shapes out of a bag. The ratio of blue shapes to red shapes are 2:1. For the blue shapes, the ratio of spheres to
Allisa [31]

Answer:

18

Step-by-step explanation:

as there are 12 red spheres there are 12*4 red cubes (48) add them ,60.Then 60/2 to find blue shapes ,30, then add the 2 and 3 to make 5 after that do 30/5 = 6 then multiply by 3

8 0
1 year ago
As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by a multiple of 1.11.
Elis [28]

Answer:

124.67cm³

Step-by-step explanation:

==>Given:

Dimensions of current can:

Height (h) = 12cm

Diameter = 6cm (radius = 3cm)

Volume of current can (V1) = 339.12 cm³

Dimensions of future cans to be increased multiple of 1.11:

height = 12cm × 1.11 = 13.32 cm

radius = 3cm × 1.11 = 3.33 cm

Volume of future can (V2) = πr²h = 3.14*3.33²*13.32

= 3.14*11.0889*13.32 = 463.791025

V2 ≈ 463.79 cm³

==>Find how much more would new cans hold = Volume of new can - volume of current can

= 463.79 cm³ - 339.12 cm³

= 124.67cm³

5 0
2 years ago
A group of eight grade 11 and five grade 12 students wish to be on the senior prom committee. The committee will consist of thre
BaLLatris [955]
5/13*4/12*3/11=5/143 I believe
7 0
1 year ago
Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]
Vadim26 [7]

Answer:

B) 28.53 unit²

Step-by-step explanation:

The diagonal AD divides the quadrilateral in two triangles:

  1. Triangle ABD
  2. Triangle ACD

Area of Quadrilateral will be equal to the sum of Areas of both triangles.

i.e.

Area of ABCD = Area of ABD + Area of ACD

Area of Triangle ABD:

Area of a triangle is given as:

Area = \frac{1}{2} \times base \times height

Base = AB = 2.89

Height = AD = 8.6

Using these values, we get:

Area = \frac{1}{2} \times 2.89 \times 8.6 = 12.43

Thus, Area of Triangle ABD is 12.43 square units

Area of Triangle ACD:

Base = AC = 4.3

Height = CD = 7.58

Using the values in formula of area, we get:

Area = \frac{1}{2} \times 4.3 \times 7.58 = 16.30

Thus, Area of Triangle ACD is 16.30 square units

Area of Quadrilateral ABCD:

The Area of the quadrilateral will be = 12.43 + 16.30 = 28.73 units²

None of the option gives the exact answer, however, option B gives the closest most answer. So I'll go with option B) 28.53 unit²

7 0
1 year ago
A psychologist would like to examine the effects of different testing methods on the final performance of college students. One
lawyer [7]

Answer:

Check the explanation

Step-by-step explanation:

One way ANOVA

The null and alternative hypothesis for this one way ANOVA is given as below:

Null hypothesis: H0: There is no significant difference in the averages of the scores for the quizzes, exams and final only.

Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.

The ANOVA table with calculations can be seen in the attached images below:

In the attached image below, we get the p-value for this one way ANOVA test as 0.0221. We do not reject the null hypothesis if the p-value is greater than the given level of significance and we reject the null hypothesis if the p-value is less than the given level of significance or alpha value.

In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.

3 0
1 year ago
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