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Andrew [12]
2 years ago
4

matematyka z plusem zad 18 str 78 , czworokąt abcd na rysunku obok jest trapezem . Oblicz pole trójkąta bmc

Mathematics
1 answer:
oee [108]2 years ago
5 0

Answer:

Ciekawe na jakiej podstawie zrobiłeś to zadanie

Step-by-step explanation:

pole trapezu ½(a+b)*h

½(4+8)*5=½*12*5=6*5=30

pole trójkąta abm

½a*h=½8*2=4*2=8

pole trójkąta cmd

½a*h=½4*3=2*3=6

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In ΔGHI, the measure of ∠I=90°, IG = 6.8 feet, and HI = 2.6 feet. Find the measure of ∠G to the nearest degree.
Luda [366]

Answer:

\angle G=20.8\approx 21^{\circ}

Step-by-step explanation:

Given: In ΔGHI, \angle I=90°, IG = 6.8 feet, and HI = 2.6 feet

To find: \angle G

Solution:

Trigonometry defines relationship between the sides and angles of the triangle.

For any angle \theta,

tan\theta = side opposite to \theta/side adjacent to \theta

In ΔGHI,

tan G=\frac{HI}{GI}

Put HI=2.6  \,\,feet\,,\,GI=6.8\,\,feet

So,

tan G=\frac{2.6}{6.8}=0.38

Therefore, \angle G=20.8\approx 21^{\circ}

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