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dezoksy [38]
2 years ago
12

Lorena solved the equation 5k – 3(2k – ) – 9 = 0. Her steps are below. 5k – 6k + 2 – 9 = 0 –k – 7 = 0 –k = 7 k = Analyze Lorena’

s work to determine which statements are correct. Check all that apply. In Step 1, she correctly distributed –3 to the parentheses. In Step 2, she combined like terms 5k and 2k. In Step 3, she applied the multiplication property of equality to isolate the variable term. In Step 4, she should have multiplied both sides by –1 to isolate the variable. Lorena found the correct solution to the linear equation.
Mathematics
2 answers:
Troyanec [42]2 years ago
8 0

1 and 4 on edg

Plz give brainliest fam

sergejj [24]2 years ago
6 0

Answer:

-In Step 1, she correctly distributed –3 to the parentheses.

-In Step 4, she should  have multiplied both sides by

–1 to isolate the variable

Step-by-step explanation:

because reasons :)) anyways have a nice day and i love youuu <333

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The curvature of the Tacoma Narrows Bridge in
8_murik_8 [283]

Answer:

Width of the arch = 105 m

Step-by-step explanation:

Function representing the width of the arch,

f(x) = -0.016(x - 52.5)² + 45

where x = width of the base of the arch or horizontal distance from arch's left end

f(x) = vertical distance of the arch

From the given quadratic function, vertex of the parabola is (52.5, 45).

Coordinates of the vertex represents,

Height of the arch = 45 m

Half of the horizontal distance from the left end = 52.5 m

Therefore, width of the bridge = 2(Half the width of the bridge from left end) = 2×52.5

= 105 m

Therefore, given bridge is 105 m wide.

4 0
2 years ago
Keisha estimates 259+372 by rounding each number to the nearest 10. What is Keisha's estimate of the sum?
nikklg [1K]

Answer:

630

Step-by-step explanation:

259 rounded to the nearest 10 is 260

372 rounded to the nearest 10 is 370

260+370=630

Hope this helps!

8 0
2 years ago
Which point on the y-axis lies on the line that passes through point C and is perpendicular to line AB?
SCORPION-xisa [38]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Which point on the y-axis lies on the line that passes through point C and is perpendicular to line AB?

A. (-6, 0)

B. (0, -6)

C. (0, 2)

D. (2, 0)

The graph of the question is attached.

Answer:

The point is (x, y) = (0, 2)

The correct option is C.

Therefore, the point (0, 2) on the y-axis lies on the line that passes through point C and is perpendicular to line AB.

Step-by-step explanation:

From the given graph, the points A and B are

(x_1, y_1) = (-2, 4) \\\\(x_2, y_2) = (2,-8) \\\\

The slope of the equation is given by

m_1 = \frac{-8 - 4 }{2 -(-2)} \\\\ m_1 = \frac{-12 }{2+2} \\\\m_1 = \frac{-12 }{4} \\\\m_1 = -3 \\\\

We know that the slopes of two perpendicular lines are negative reciprocals of each other.

m_2 = - \frac{1}{m_1}

So the slope of the other line is

m_2 = \frac{1 }{3} \\\\

Now we can find the equation of the line that is perpendicular to the line AB and passes through the point C.

From the graph, the coordinates of point C are

(x_1, y_1) = (6, 4)

The point-slope form is given by,

y - y_1 = m(x -x_1)

Substitute the value of slope and the coordinates of point C

y - 4 = \frac{1 }{3} (x - 6)\\\\

To get the y-intercept, substitute x = 0  

y - 4 = \frac{1 }{3} (0 - 6) \\\\y - 4 = \frac{-6 }{3}\\\\y - 4 = -2\\\\y = 4 -2 \\\\y = 2 \\\\

So, the point is

(x, y) = (0, 2)

The correct option is C.

Therefore, the point (0, 2) on the y-axis lies on the line that passes through point C and is perpendicular to line AB.

6 0
2 years ago
Consider the graph of the line y = one-halfx – 4 and the point (−4, 2). The slope of a line parallel to the given line is . A po
Musya8 [376]

the awnser is (3,-5)

8 0
2 years ago
Read 2 more answers
A parabolic satellite dish reflects signals to the dish’s focal point. An antenna designer analyzed signals transmitted to a sat
ivolga24 [154]

Answer:

c=\frac{16}{39}

Step-by-step explanation:

The probability density function is :

f(x)=c(1-\frac{1}{16}x^{2})

With 0 < x < 3

To be a valid probability density function :

\int\limits^b_a {f(x)} \,dx=1

Where a < x < b

And also

f(x) ≥ 0 for a < x < b

Applying this to the probability density function of the exercise :

\int\limits^3_0 {c(1-\frac{1}{16}x^{2})} \, dx=1

c\int\limits^3_0 {(1-\frac{1}{16}x^{2})} \, dx=1

c(3-\frac{1}{16}\frac{3^{3}}{3})=1

c(\frac{39}{16})=1

c=\frac{16}{39}

We can verify by replacing ''c'' in the original probability density function and integrating :

\int\limits^3_0 {\frac{16}{39}(1-\frac{1}{16}x^{2})} \, dx=

=\frac{16}{39}.(3)-\frac{1}{39}.(\frac{3^{3}}{3})=\frac{16}{13}-\frac{3}{13}=\frac{13}{13}=1

Also, f(x) ≥ 0 for 0 < x < 3

4 0
2 years ago
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