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KIM [24]
2 years ago
13

On the grid draw a scaled copy of quadrilateral ABCD with a scale factor 2/3

Mathematics
1 answer:
Tamiku [17]2 years ago
6 0

Answer:

Attached diagram A'B'C'D'

Step-by-step explanation:

Given is a quadrilateral ABCD. It says to draw a dilated version with a scale factor 2/3.

We see that scale factor is less than 1 which means it shrinks the image to a smaller one.

To draw a scaled copy, we need to find the lengths of its sides.

To do so, we can draw the diagonals AC & BD, and they intersect at origin O(0,0) such that OA= -2, OB= 2, OC= 4, OD= -4.

Applying a scale factor of 2/3, we get OA' = -4/3, OB' = 4/3, OC' = 8/3, OD' = -8/3.

So we have attached a scaled copy A'B'C'D' of quadrilateral ABCD with a scale factor 2/3.

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2 years ago
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the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

Answer:

a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

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2 years ago
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The problem asks for how many gallons of gas she will safe in a five-day work work week. So first you need to compute how many miles that would be. 

54 miles/day x 5days =  270 miles

So in a five day work week, she will travel 270 miles.

Now to see how much gas she will save, compute how many gallons she will use up for each car, given the mpg of each and find the difference. 

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Second model: 27 mpg
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This means that with the second model, she will have used up 10g in a 5-day work week. 

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answer

<span>the weight of the baby was 5 kg</span>
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2 years ago
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