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KIM [24]
2 years ago
13

On the grid draw a scaled copy of quadrilateral ABCD with a scale factor 2/3

Mathematics
1 answer:
Tamiku [17]2 years ago
6 0

Answer:

Attached diagram A'B'C'D'

Step-by-step explanation:

Given is a quadrilateral ABCD. It says to draw a dilated version with a scale factor 2/3.

We see that scale factor is less than 1 which means it shrinks the image to a smaller one.

To draw a scaled copy, we need to find the lengths of its sides.

To do so, we can draw the diagonals AC & BD, and they intersect at origin O(0,0) such that OA= -2, OB= 2, OC= 4, OD= -4.

Applying a scale factor of 2/3, we get OA' = -4/3, OB' = 4/3, OC' = 8/3, OD' = -8/3.

So we have attached a scaled copy A'B'C'D' of quadrilateral ABCD with a scale factor 2/3.

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The ratio of the perimeter of square RSTU to the perimeter of square WXYZ is 1 to 3. The area of square RSTU is 36 square inches
Ainat [17]
√36 square inches = 6 inches (length of sq RSTU)
6 inches x 4=24 inches (per. of sq RSTU)
-----------------------------------
1u=24 inches
3u=24 inches x 3=72 inches (per. of sq WXYZ)
-----------------------------------
72 inches ÷ 4=18 inches (length of sq WXYZ)
18 inches x 18 inches = 324 square inches( area of sq WXYZ)

Ans: 324 square inches

5 0
2 years ago
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With an 18% discount, Joan was able to save $13.23 for a coat. What was the original price of the coat?
strojnjashka [21]
Hi there!

First we need to realise that the 18% discount equals John's savings. Therefore 18% of the original price is $13.23.

When we know 18% of the price, we can also find 1% of the total price.

18% = $13.23
Divide both sides by 18.

1% = $0.735
To find the total price, which equals 100%, we know only need to multiply both sides by 100.

100% = $73.50.
Therefore, the original price for the coat is $73.50.

~ Hope this helps you!
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2 years ago
A quality-control inspector is testing a batch of printed circuit boards to see wheater they are capable of performing in a high
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Answer:

see explaination

Step-by-step explanation:

Here the null hypothesis is that the PCB survives against the alternate that the PCB 'does not survive'. The test says that the PCB will survice if it is classified as 'good'; or, it will not survive if it is classifies as 'bad'.

a. The Type II error is the error committed when a PCB which cannot actually survive is classified as 'good'.

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Find the area of the trapezoidal cross-section of the irrigation canal shown below. Your answer will be in terms of h, w, and θ.
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A child who is trick-or-treating chooses a lollipop at random from a bowl of lollipops with mean weight 1.5 oz and standard devi
son4ous [18]

Answer:

The expected combined weight of the child's lollipop and two chocolate bars is 5.5 oz.

Step-by-step explanation:

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Addition of normal variables:

The mean is the sum of the means.

Find the expected combined weight of the child's lollipop and two chocolate bars.

Child lollipop: Mean 1.5 oz

Chocolate bars: Mean 2 oz

One lollipop and 2 bars combined

The mean will be 1.5 + 2*2 = 5.5 oz

The expected combined weight of the child's lollipop and two chocolate bars is 5.5 oz.

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