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MrMuchimi
2 years ago
4

Given: KPST is a trapezoid, KP=ST, MN is a midsegment, MN=20, h=15, PS:KT=3:7 Find: KS and KP

Mathematics
2 answers:
Nookie1986 [14]2 years ago
8 0

Answer:

The length of KS is 25 units and the length of KP is 17 units.

Step-by-step explanation:

Given information: KPST is a trapezoid, KP=ST, MN is a mid segment, MN=20, h=15, PS:KT=3:7 .

Since two sides of the trapezoid are equal therefore it is an isosceles trapezoid.

The midsegment of a trapezoid is a line segment which connects the midpoints of the non-parallel sides.

The length of mid segment is average of length of parallel lines. The length of mid segment is 20.

It is given that PS:KT=3:7. Let the length of sides be 3x and 7x respectively.

\frac{3x+7x}{2}=20

\frac{10x}{2}=20

5x=20

x=4

The value of 3x and 7x are 12 and 28 respectively. So, the length of sides PS and KT is 12 and 28 respectively.

Use pythagoras in triangle AKP.

AK^2+AP^2=KP^2

(8)^2+(15)^2=KP^2

\sqrt{64+225}=KP

tex]\sqrt{289}=KP[/tex]

17=KP

Use pythagoras in triangle BKS.

BK^2+BS^2=KS^2

(20)^2+(15)^2=KS^2

\sqrt{400+225}=KS

tex]\sqrt{625}=KS[/tex]

KS=25

Therefore length of KS is 25 units and the length of KP is 17 units.

GREYUIT [131]2 years ago
8 0

Answer:

KS=25, KP=17

Step-by-step explanation:

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