Please Answer , question in the screenshot
1 answer:
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The complete question in the attached figure
we know that
the equation of a parabola is
y=a(x-h)²+k
where
(h,k) is the vertex --------> (h,k)--------> (-1,2)
so
y=a(x+1)²+2
point (2,20)
for x=2
y=20
20=a(2+1)²+2--------> 20=a*9+2--------> 9*a=18---------> a=2
the equation of a parabola is
y=a(x+1)²+2-------> y=2(x+1)²+2
therefore
the answer is the option
<span>C) f(x) = 2(x + 1)2 + 2</span>
we know that
the equation of a parabola is
y=a(x-h)²+k
where
(h,k) is the vertex --------> (h,k)--------> (-1,2)
so
y=a(x+1)²+2
point (2,20)
for x=2
y=20
20=a(2+1)²+2--------> 20=a*9+2--------> 9*a=18---------> a=2
the equation of a parabola is
y=a(x+1)²+2-------> y=2(x+1)²+2
therefore
the answer is the option
<span>C) f(x) = 2(x + 1)2 + 2</span>
Answer:
Intercepts at (-1, 0) and (0, 1).
Step-by-step explanation:
The double intercept form for the equation of a line is
ax + by = 1
-1 = -y + x
<em> y = 0 </em>
<em> </em>x = -1 Multiply each side by -1
-x = 1
The <em>x-intercept</em> is at (-1, 0).
=====
<em> x = 0 </em>
-1 = -y Multiply each side by -1
y = 1
The <em>y-intercept</em> is at (0, 1).
=====
The graph (see below) is a straight line passing through the points (-1, 0) and (0, 1).
