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AleksandrR [38]
2 years ago
3

The American Veterinary Medical Association believes that half of veterinary clinics do not treat large animals (cows, horses, e

tc.). The American Veterinary Medical Association conducted a survey of veterinary clinics to estimate the proportion that do not treat large animals (cows, horses, etc.). In the survey of 120 randomly selected veterinary clinics throughout the country, 88 responded they do not treat large animals. The test statistic for the above hypothesis test about the proportion of clinics that do not treat large animals is... (Round your answer to two decimal places)
Mathematics
2 answers:
Alenkinab [10]2 years ago
8 0
Percentage = 88/120 × 100 ≈ 73.33 %
LuckyWell [14K]2 years ago
7 0

Answer:

The test statistic for the above hypothesis test about the proportion of clinics that do not treat large animals is wrongly estimated

Step-by-step explanation:

This is a simple distribution principle used in testing. There are only two variables and we are given the total number of observations in the test.

Total observations = 120

Number of clinics who did not treat large animals = 88

Number of clinics that would operate large animals = 120 - 88 = 32

Percentage of clinics that do not treat large animals = (88 / 120) x 100

Percentage of clinics that do not treat large animals = 73%

Since 73% is significantly large than 50% in hypothesis, hence it is not accurate

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5. The table shows the amount of pet food in cups remaining in an automatic feeder as
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2 years ago
If ED = 5y + 6 and DB = y + 30, find the value of y. Then find ED, DB, and EB.
Gemiola [76]

Answer:

Part 1) The value of y=6

Part 2) ED=36, DB=36 and EB=72

Step-by-step explanation:

In this problem we know that

ED=DB -----> equation A

EB=ED+DB -----> equation B

The point D is the midpoint ED

see the attached figure to better understand the problem

step 1

Find the value of y

Substitute the given values in the equation A

5y+6=y+30

solve for y

5y-y=30-6

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y=6

step 2

Find the value of ED,DB and EB

ED=5y+6

substitute the value of y

ED=5(6)+6=36

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ED=DB

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DB=36

Find the value of EB

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3 0
2 years ago
Kylie drew a circle with a diameter of 8 cm. Paige drew a circle with a radius of 3 cm. Approximately how much larger is the are
Alex787 [66]

Hello!

<h2>Answer:</h2>

\boxed{ \bf The~area~of~Kylie's~circle~is~approximately~22~cm^2~larger~than~Paige's.}

<h2>__________________________________________________</h2><h2>Explanation:</h2>

We'll start by calculating the areas of Kylie and Paige's circles.

Kylie's Circle:

A = πr²

Since we need the radius for the formula, we must divide the diameter in half to get it.

r = d ÷ 2

r = 8 ÷ 2

r = 4

Now, let's substitute our values into the formula.

A = 3.14 × 4²

A = 3.14 × 16

A = 50.24 cm²

Paige's Circle:

A = πr²

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A = 3.14 × 9

A = 28.26 cm²

We can round both of these areas to the nearest whole number. Then, we must subtract Paige's circle area by Kylie's.

50 - 28 = 22

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