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Cloud [144]
2 years ago
10

One day, Fiona and Heidi each bought coins at a coin shop. The equation f(x)=3x+12 represents the value of Fiona’s coin, in doll

ars, x years later. The graph shows the value of Heidi’s coin, in dollars, x years later.
Select from the drop down menus to complete the statement.


When they bought their coins, _____

A- Fiona’s
B- Heidi’s

was worth ____
A- $3
B- $6
C- $9
D- $12

more than ____ coin.
A- Fiona’s
B- Heidi’s

Mathematics
2 answers:
Dvinal [7]2 years ago
5 0
1 a
2b
3b
This is the Sancerre I got
liq [111]2 years ago
3 0

Answer:

A- Fiona’s,

B- $6

B- Heidi’s

Step-by-step explanation:

Here, the equation that represents the value of Fiona’s coin, in dollars, x years later is,

f(x) = 3x + 12

Initially, x = 0,

Thus, the value of the coin when Fiona bought,

f(0) = 3(0) + 12 = $ 12,

Also, the graph represents the value of Heidi’s coin, in dollars, x years later.

By the graph, if x = 0 ( initially ),

y = 6

That is, when Heidi bought the coin its value is $ 6,

Also, 12 - 6 = 6

Hence, when they bought their coins, Fiona’s was worth $6 more than Heidi’s coin.

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olivia purchases gifts for mothers day. thev first is a pair of sunglasses for $16.35 and the second is a bracelet . her total i
mash [69]

Answer:

$23.40

Step-by-step explanation:

You have to subtract $39.75 by $16.35 as $39.75 is the total and we have to find out how much the bracelet is. There is also no regrouping.

7 0
2 years ago
The functions $f$ and $g$ are defined as follows: \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\quad\text{and}\quad g(x) = \dfrac{\sqrt{x+1}}
CaHeK987 [17]

Answer:

The answer is "domain and range are different".

Step-by-step explanation:

Given:

f(x) = \sqrt{\frac{x+1}{x-1}}\\\\g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\

Solve f(x) to find domain and range:

for element x: R:

⇒ x \leq -1 \ \ \ and \  \ \  x > 1 range:

for  \ \ f(x) \times element : 0 \leq f(x)< 1 \ \ \ or \ \ f(x)>1

g(x) =\frac{\sqrt{x+1}}{\sqrt{x-1}}\\

Solve for domain:

⇒ \ when \ x \ element \ R: \ \ \ x>1  

Solve for range:  

⇒ g(x) \times element  R : g(x)>1

So, the value of the method f(x) and g(x) (range and domain) were different.  

5 0
2 years ago
The heights of students at a college are normally distributed with a mean of 175 cm and a standard deviation of 6 cm. One might
frosja888 [35]

Answer:

25

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 175cm

Standard deviation = 6 cm

Percentage of students below 163 cm

163 = 175 - 2*6

So 163 is two standard deviations below the mean.

By the Empirical rule, 95% of the heights are within 2 standard deviations of the mean. The other 100-95 = 5% are more than 2 standard deviations of the mean. Since the normal distribution is symmetric, 2.5% of them are more than 2 standard deviations below the mean(so below 163cm) and 2.5% are more than two standard deviations above the mean.

2.5% of the students have heights less than 163cm.

Out of 1000

0.025*1000 = 25

25 is the answer

8 0
2 years ago
Read 2 more answers
Angela drove 82 miles on Monday. She drove 94 on Tuesday. To the nearest hundred, how many miles did Angela drive over the two d
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You just simply add
82+94= 166
4 0
2 years ago
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A middle school band has 45 sixth and seventh graders The ratio of sixth to seventh graders is 2 to 3 how many sixth graders are
AnnyKZ [126]

Answer:

  18

Step-by-step explanation:

There are 2+3 = 5 ratio units representing 45 band members, so each ratio unit represents 45/5 = 9 band members.

The 2 ratio units of sixth graders represent 2×9 = 18 sixth grade band members.

5 0
2 years ago
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