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photoshop1234 [79]
2 years ago
8

To prepare for a triathlon, Amanda starts from position A and rides her bike along a straight road for 12 miles to reach positio

n B. At B, she turns left and rides along another straight road for 15 miles to reach position C. At C, she turns left again and rides 20 miles along a straight road to return to A. In , what are m∠A, m∠B, and m∠C, respectively?

Mathematics
2 answers:
Dominik [7]2 years ago
6 0

Answer:

48.35°, 94.94°, 36.71°

Step-by-step explanation:

Sergio [31]2 years ago
3 0

Answer:


Step-by-step explanation:

Let's draw the given information first for better understanding . Check the image attached.

We can use cosine rule to find the angles .

for angle A ,

Cos A =\frac{b^2+c^2-a^2}{2bc}

Cos A =\frac{20^2+12^2-15^2}{2*20*12}

Cos A =\frac{319}{480}

m∠A = 48.35 degrees

Similarly for angle B

Cos B =\frac{a^2+c^2-b^2}{2bc}

Cos B =\frac{15^2+12^2-20^2}{2*15*12}

Cos B =\frac{-31}{360}

m∠B = 94.94 degrees

Now use A+B+C=180 degrees

48.35+94.94+C=180

C=180-48.35-94.94

m∠C = 36.71 degrees

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timofeeve [1]
The steepest graph is gonna have the largest slope....but u have to use the absolute value of the slopes to compare

y = -2x.....slope is -2....| -2 | = 2
y = -1/2x...slope is -1/2....| -1/2 | = 1/2
y = 3/2x....slope is 3/2 (or 1 1/2)...| 1 1/2} = 1 1/2
y = 5/2x...slope is 5/2 (or 2 1/2)...| 2 1/2| = 2 1/2

so the steepest graph is : y = 5/2x
4 0
2 years ago
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The distribution of average wait times in drive-through restaurant lines in one town was approximately normal with mean \mu = 18
Fynjy0 [20]

Answer:

193

Step-by-step explanation:

8 0
2 years ago
What is the domain of validity for csctheta =start fraction 1 over sine theta end fraction? (1 point) all real numbers all real
dem82 [27]
We know the following relationship:

csc(\theta)=\frac{1}{sin(\theta)}

The domain of a function are the inputs of the function, that is, a function f is a relation that assigns to each element x in the set A exactly one element in the set B. The set A is the domain (or set of inputs) of the function and the set B contains the range (or set of outputs).Then applying this concept to our function csc(\theta) we can write its domain as follows:

1. D<span>omain of validity for csc(\theta):
</span>
D: \{\theta \in R/ sin(\theta) \neq 0 \} \\ In words: All \ \theta \ that \ are \ real \ values \ except \ those \ that \ makes \ sin(\theta)=0 
 
When:

sin(\theta)=0?

when:

\theta=..., -2\pi,-\pi,0,\pi,\2pi,3pi,...,k\pi

where k is an integer either positive or negative. That is:

sin(k\theta)=0 \ for \ k=...,-2,-1,0,1,2,3,...

To match this with the choices above, the answer is:

<span>"All real numbers except multiples of \pi"

</span>
2. which identity is not used in the proof of the identity 1+cot^{2}(\theta)=csc^{2}(\theta):

This identity can proved as follows:

sin^2{\theta}+cos^{2}(\theta)=1 \ Dividing \ by \ sin^{2}(\theta) \\ \\ \therefore \frac{sin^2{\theta}}{sin^{2}(\theta)}+\frac{cos^{2}(\theta)}{sin^{2}(\theta)}=\frac{1}{sin^{2}(\theta)} \\ \\ \therefore 1+cot^{2}(\theta)=csc^{2}(\theta)

The identity that is not used is as established in the statement above:

<span>"1 +cos squared theta over sin squared theta= csc2theta"

Written in mathematical language as follows:

</span>\frac{1+cos^{2}(\theta)}{sin^{2}(\theta)}=csc^{2}(\theta)<span>


</span>
4 0
2 years ago
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s.Lewis has a net spendable income of $2,000 per month. He sets up the following transportation budget for himself. 3. Transport
shtirl [24]

Answer:

D.He has not budgeted for all of the expenses in the subcategories.

Step-by-step explanation:

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b. Gas/Oil 120

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d. License/Registration 8

e. Taxes 2

f. Maintenance/Repair

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Therefore, the corrct answer is option

D.He has not budgeted for all of the expenses in the subcategories.

4 0
2 years ago
According to the Rational Root Theorem, which is a factor of the polynomial f(x) = 3x3 – 5x2 – 12x + 20?
Harlamova29_29 [7]

3x^3 – 5x^2 – 12x + 20

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= x^2(3x - 5) - 4(3x - 5)

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= (3x - 5)(x + 2)(x - 2)


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Answer:

D.) 3x – 5

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2 years ago
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