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Sholpan [36]
2 years ago
15

Complete the proof of the exterior angle theorem. Given: ∠4 is an exterior angle of △ABC. Prove: m∠1+m∠2=m∠4 Answer: Statement R

eason 1. ∠4 is an exterior angle of △ABC. 1. 2. ∠3 and ∠4 form a linear pair. 2. 3. ∠3 is supplementary to ∠4. 3. 4. m∠3+m∠4=180° 4. 5. 5. Triangle Sum Theorem 6. m∠1+m∠2+m∠3=m∠3+m∠4 6. 7. 7.

Mathematics
2 answers:
andrezito [222]2 years ago
7 0

Answer:

1.   given

2.  linear pair property

3.  straight line property

4.  angle 3 is supplementary to angle 4

5. m<1 + m<2 + m<3 = 180 --> Triangle Sum Theorem

6.  statement 4 and 5

7. m<1 + m<2 = m<4 --> subtraction property

Step-by-step explanation:

i just did the test and i checked over these answers and its right :)

have a great day

Nataly_w [17]2 years ago
5 0

Answer:


Step-by-step explanation:

Statement                                                                              Reason

1. ∠4 is an exterior angle of ΔABC                                         Given

2. ∠3 and ∠4 form a linear pair                                    Linear pair property

3. ∠3 is supplementary to ∠4                                     Straight line property

4. m∠3+m∠4=180°                                                ∠3 is supplementary to ∠4      

5. m∠1+m∠2+m∠3=180°                                           Triangle sum theorem

6.m∠1+m∠2+m∠3= m∠3+m∠4                                   Statement 4 and 5

7. m∠1+m∠2=m∠4                                                     Subtraction property

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Answer:

The answer is below

Step-by-step explanation:

Let x represent the number of small hat purchased, y represent the number of medium hat purchased and z represent the number of large hat purchased.

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x + y + z = 47    (1)

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5.5x + 6y + 7z = 302     (2)

He purchases three times as many medium hats as small hats, hence:

y = 3x

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Represent equations 1, 2 and 3 in matrix form gives:

\left[\begin{array}{ccc}1&1&1\\5.5&6&7\\-3&1&0\end{array}\right] \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}47\\302\\0\end{array}\right] \\\\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}1&1&1\\5.5&6&7\\-3&1&0\end{array}\right] ^{-1} \left[\begin{array}{c}47\\302\\0\end{array}\right] \\\\\\ \left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}6\\18\\23\end{array}\right]

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Answer:

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Step-by-step explanation:

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