Answer:
20.78feet
Step-by-step explanation:
The question made us to understand that the man is standing and also there is angle of elevation, then we need to draw a right triangle having a base equal to 36 feet with an angle from the base to the top of the pole which is 30 degrees.
tan= opposite side / adjacent side
Let height of the pole =h
Tan(30)= h/36
But tan 30degree= 1/√3
h= 36 × 1/√3
h= 20.78feet
Therefore, the height of the pole= 20.78feet
CHECK THE ATTACHMENT FOR DETAILED FIGURE
Answer:
4.43
Step-by-step explanation:
7.90
- 3.47
__________
4. 4 3
I couldn't regroup but of you cross out 0 and put 10, 10-7= 3
and you have to borrow one from 9 and make it 8 and 8-4=4
Answer:the original height of the candle is 14.8 inches
Step-by-step explanation:
A Candlestick burns at a rate of 0.2 inches per hour. It means that the height of the candle is decreasing by 2 inches per hour. This decrease is in arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
d = - 0.2 (it is decreasing)
n = 8
T8 = 13.4 inches
We want to determine the value of the first term, a. Therefore,
13.4 = a - 0.2(8 - 1)
13.4 = a - 1.4
a = 13.4 + 1.4 = 14.8 inches
Answer:
Annie walked 1 11/12 miles
Step-by-step explanation:
Trail= 4 1/2 miles
Annie ran the first 2/3 miles
Remaining miles= Total miles - Miles covered first
= 4 1/2 - 2/3
= 9/2 - 2/3
= 27-4 / 6
= 23/6 miles
Remaining miles = 23/6 miles
Annie walked for 1/2 of the remaining distance
1/2 of the remaining miles= 1/2 × 23/6
=23 / 12
= 1 11/12
Annie walked 1 11/12 miles
Answer:
81%
Step-by-step explanation:
Let 'L' be the dominant and 'l' e the recessive allele for ‘lazybuttness’.
Since ‘lazybuttness’ is an autosomal dominant condition, the 19% of students affected by the condition correspond to the homozygous dominant (LL) and heterozygous (Ll) genotypes. Therefore, the rest of the population has the homozygous recessive genotype (ll) and is not affected. The frequency of students not affected is:
F = 100% - 19% = 81%
