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Licemer1 [7]
1 year ago
14

A tourist looks out from the observation deck of the Space Needle in Seattle. The deck is at a height of 520 ft. She sees her fr

iend on the ground below at an angle of depression of 80.2 What is the distance between the two? Round your answer to the nearest tenth of a foot.

Mathematics
1 answer:
WARRIOR [948]1 year ago
6 0

Answer:

Last option 527.7 ft

Step-by-step explanation:

From the diagram attached we can see the angle of depression is 80.2 which is equal to ∠ACB (alternate angles)

Height of the deck AB = 520 ft. and we have to calculate the distance H between the tourist and her friend.

Sin ∠ACB = \frac{AB}{AC}

Now we apply sin rule sin 80.2 = \frac{520}{H}

.9854=\frac{520}{H}

H = \frac{520}{.9854} = 570 ft

So the tourist and her friend are 527.7 ft apart.

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31.5 feet is the imput
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Step-by-step explanation:

CORRECTED QUESTION

Joe walks on a treadmill at a constant rate. The equation d=4t describes the relationship between t, the time he walks in hours, and d, the distance he walks in miles. Which of the graph best describes the relationship?

The equation d=4t is a linear equation.

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2 years ago
which figures do not have lateral area?
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1 year ago
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never [62]

Answer:

2\sqrt{2}\ ft\ longer

Step-by-step explanation:

<u>Area Of A Cube </u>

Suppose a cube with side length s, the area of one side is

A_s=s^2

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A=6A_s=6s^2

But if we have the area, we can solve the above formula for s to get

A=6s^2

\displaystyle s=\sqrt{\frac{A}{6}}

We have two different cubes with areas 1,200 square inches and  768 square inches. Let's compute their side lengths

\displaystyle s_1=\sqrt{\frac{1,200}{6}}=\sqrt{200}

\displaystyle s_1=10\sqrt{2}\ ft

\displaystyle s_2=\sqrt{\frac{768}{6}}=\sqrt{128}

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Answer:

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