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1 year ago

Suppose the sample size for this study was n=2 instead of n=70. What would be the shape of the distribution of sample means

Mathematics

1 answer:

s344n2d4d5 [400]1 year ago

7 0

Answer :

The shape of the distribution of the sample usually contains the given two points :

1. The sampling distribution is skewed for small sample sizes. Also, the distribution will be non-normal if the sample size is small

2. The shape of the sampling distribution gets more and more normal-like (bell shaped) as the sample size increases

For sample size, n = 2

The sampling distribution will be skewed for this sample size

For sample size, n = 70

The shape of the sampling distribution for sample size of 70 will be more normal as compared to that of sample size of 2

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Madden and Jenn both worked at the coffee shop today. Madden's total cups of coffee made is represented by f(x); and Jenn's tota

AnnZ [28]

Answer:

The answer is D. 12x - 3.

Step-by-step explanation:

To add these functions, we just add the terms.

f(x) + g(x) = (7x - 4) + (5x + 1)

7x - 4 + 5x + 1 | Simplify

7x + 5x - 3

12x - 3.

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1 year ago

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Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

FromTheMoon [43]

Answer:

Here is the question attached with.

$m\angle CEA =90 \ (deg)$

$m\angle BEF=135\ (deg)$

$\angle CEF$ is a straight line.

$\angle AEF$ is a right angled triangle.

Options $1,4,5,6$ are correct answers.

Step-by-step explanation:

⇒As $\ ray\ AE$ is ⊥ $FEC$ so it will forms right angled triangle then $m\angle CEA =90\ (deg)$ .

⇒Measure of $\angle BEF =135\ (deg)$ as $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ is the bisector of $\angle AEC$ ,meaning that $\angle AEB$ is half of $\angle AEC$ so $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ is a straight line as the angles measure over it is $180\ (deg)$ .

⇒Measure of $\angle AEF = 90\ (deg)$ from linear pair concept.

As $\angle CEA + \angle AEF = 180\ (deg)$ ,plugging the values of $m\angle CEA =90\ (deg)$ we have $\angle AEF = 90\ (deg)$ .

The other two options are false as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it is exceeding $180\ (deg)$ whereas $\angle CEF$ is a

straight line.

And $m\angle CEB=2(m\angle CEA)$ is not true.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

So we have total $4$ answers.

The correct options are $1,4,5,6$ .

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2 years ago

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taurus [48]

Answer:

221 g

The up pinned pic is of inverse variation typed answer.. If u want word problem type answer here are the steps (EVEN IF THE STEPS ARE DIFFERENT ANSWERS REMAIN SAME)

Step-by-step explanation:

Mass of wire from 22cm = 374g

Mass of wire from 1 cm = 374÷22 = 17g

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1 year ago

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Phoenix [80]

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mina [271]

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2 years ago