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uranmaximum [27]
2 years ago
7

A company claims that its tablet computers have an average recharge time of 3 hours. Using a random sample of 50 company tablet

computers, a consumer group determines a mean recharge time of 2.5 hours with a standard deviation of 0.3 hours.
Mathematics
2 answers:
kondor19780726 [428]2 years ago
7 0

Solution:

The Statement made by company about it's tablet computer,

Average recharge time = 3 Hours

As, to check whether the company claim is illegal or true

A random sample of 50 company tablet computers, and their recharging time is noted.

As, we have taken random sample , so standard deviation will come into consideration whether company claim is true or false.

Mean recharge time of 50 company tablet computers=  2.5 hours

Standard deviation of 50 company tablet computers=  0.3 hours

So, Mean standard deviation =

   2.5 \pm0.3\\\\ 2.5 -0.3 \leq {\text{Mean standard deviation}}\leq 2.5+0.3\\\\ 2.2\leq {\text{Mean standard deviation}}\leq 2.8

So, Claim made by company , that its tablet computers have an average recharge time of 3 hours is  Approximately true.

As , there is fluctuation of (3 hours - 2.2 hours =3-2.12=48 minutes ) and (3 hours -2.8 hours=3-2.48=12 minutes), which is not so much ,so we can believe on this company and buy the product (that is tablet computers) of this company.

finlep [7]2 years ago
7 0

The answer for What is the null hypothesis, for this situation? is µ=3,  The answer for the following question is What is the alternative hypothesis, for this situation? is µ<3,  the answer for the following question The _________ hypothesis represents the statistical claim that the company’s tablet computers have an average recharge time of less than 3 hours. is alternative

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Answer:

150 short sleeves ordered

100 long sleeves ordered

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2 years ago
Jacinta buys 4 pounds of turkey and 2 pounds of ham. She pays a total of $30, and the turkey costs $1.50 less per pound than the
marissa [1.9K]

Given

jacinta buys 4 pounds of turkey and 2 pounds of ham & pays a total of $30, turkey costs $1.50 less per pound than the ham.

find out the combined cost of 1 pound of turkey and 1 pound of ham

To proof

As given in the question

jacinta buys 4 pounds of turkey and 2 pounds of ham

total pay by jacinta = $30

let us assume that the price of the ham = x

as given in the question

turkey costs $1.50 less per pound than the ham

turkey costs becomes = x - 1.50

then the equation becomes

30 = 4 (x - 1.50) + 2x

30 = 4x + 2x - 6

36 = 6x

x = 6

thus

ham cost per pound = $6

turkey cost per pound = 6 - 1.50

                                    = $ 4.5

Now find out

cost of 1 pound of turkey + 1 pound of ham = $ 6 + $ 4.5

                                                                       = $ 10.5

Hence proved





5 0
2 years ago
Read 2 more answers
Which reaction describes a beta emission?  2659Fe→ 2759Co +  −10e  88226Ra→ 86222Rn +  24He ��94239Pu +  24He→ 96242Cm  +  01n  
shepuryov [24]

Correct question:

Which reaction describes a beta emission?  2659Fe→ 2759Co +  −10e,   88226Ra→ 86222Rn +  24He, 94239Pu +  24He→ 96242Cm  +  01n,  54118Xe→ 53118I +  +10e

Answer:

2659Fe→ 2759Co + 1e

Step-by-step explanation:

General equation for beta decay is given as;

^A_zX -> \ ^A_{z+1}Y +\  ^0_{-1} \beta

where;

A is the atomic mass of the element

z is atomic number of the element

X is the parent atom

Y is the daughter element

β is beta emission

In beta emission, there is loss of one electron and zero proton, the will cause the daughter element to gain on electron in order to balance the reaction.

Based on beta decay equation above, we select the reaction that describes beta emission.

2659Fe→ 2759Co + 1e

Here;

A = 59

z = 26

z + 1 = 27

5 0
2 years ago
Read 2 more answers
Circle C has radius of 10 cm. Each of points B and D is on the midpoint of the radius. Find the area of the shaded region.
olya-2409 [2.1K]
Simple :)
Area of shaded part = are of 1/4 circle - area of both triangles.
Are of circle = pie r^2 so 100x3.14 = 314 cm2.
Area of triangle AOB= area of triangleDOE = bh/2= 5x10/2= 25 each
However, the traingles share a common area which is quad DOB(I)
Lets take traingle AOE, whose are is bh/2=10x10/2=50cm2.
50-area of triangle A(I)E= 50-(
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2 years ago
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The amount of time it takes for a student to complete a statistics quiz is uniformly distributed (or, given by a random variable
topjm [15]

Answer:

(A) 0.15625

(B) 0.1875

(C) Can't be computed

Step-by-step explanation:

We are given that the amount of time it takes for a student to complete a statistics quiz is uniformly distributed between 32 and 64 minutes.

Let X = Amount of time taken by student to complete a statistics quiz

So,   X ~ U(32 , 64)

The PDF of uniform distribution is given by;

    f(X) = \frac{1}{b-a} ,  a < X < b      where a = 32 and b = 64

The CDF of Uniform distribution is P(X <= x) = \frac{x-a}{b-a}

(A) Probability that student requires more than 59 minutes to complete the quiz = P(X > 59)

   P(X > 59) = 1 - P(X <= 59) = 1 - \frac{x-a}{b-a} = 1 - \frac{59-32}{64-32} = 1-\frac{27}{32} = 0.15625

(B) Probability that student completes the quiz in a time between 37 and 43 minutes = P(37 <= X <= 43)  = P(X <= 43) - P(X < 37)

    P(X <= 43) = \frac{43-32}{64-32} = \frac{11}{32} = 0.34375

    P(X < 37) = \frac{37-32}{64-32} = \frac{5}{32} = 0.15625

    P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875

(C) Probability that student complete the quiz in exactly 44.74 minutes

     = P(X = 44.74)

The above probability can't be computed because this is a continuous distribution and it can't give point wise probability.

3 0
2 years ago
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