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Bond [772]
2 years ago
4

Terri needs 250$ to buy Christmas gots this year. She has $75 saved already, and she is saving $45 each week

Mathematics
2 answers:
Naddik [55]2 years ago
7 0
In 6 weeks Terri will have the money she needs for gifts
sammy [17]2 years ago
4 0

Answer:

4 weeks more to get $250

or needs to save $175 more

Step-by-step explanation:

So 250-75=175

and 175/45=3.9

So it will take her about 4 weeks more to save up enough money or she needs to save $175 more

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The number of bacteria in a petri dish on the first day was 113 cells. If the number of bacteria increase at a rate of 82% per d
Tresset [83]

Answer:

4107 cells

Step-by-step explanation:

From the question, we have the following values:

Day 1 : 113 cells

Number of cells increases by day by 82%

Hence,

Day 2

113 × 82% = 92.66cells

Hence, Total number of bacteria cells for Day 2 = 113 + 92.66 = 205.66cells

Day 3

205.66 × 82% = 168.6412 cells

Hence, Total number of bacteria cells for Day 3 = 168.6412 + 205.66 = 374.3012 cells

Day 4

374.3012 × 82% = 306.926984 cells

Hence, Total number of bacteria cells for Day 4 = 306.926984 + 374.3012 = 681.228184 cells

Day 5

681.228184 × 82% = 558.60711088 cells

Hence, Total number of bacteria cells for Day 5 = 558.60711088 + 681.228184 = 1239.8352949 cells

Day 6

1239.8352949 × 82% = 1016.6649418 cells

Hence, Total number of bacteria cells for Day 5 = 1016.6649418 + 1239.8352949 = 2256.5002367 cells

Day 7

2256.5002367 × 82% = 1850.3301941 cells

Hence, Total number of bacteria cells for Day 7 = 1850.3301941 + 2256.5002367 = 4106.8304308 cells

Approximately to nearest whole number, the total number of bacteria cells that would be present after 7 days = 4107 cells

3 0
2 years ago
A waitress works 1.75 hours less in the afternoon than in the evening. If she works 5      1/8
gayaneshka [121]
Let x be the number of hours that the waitress works in the evening.

We know for our problem that she works 5 \frac{1}{8} in the afternoon and that she works <span>1.75 hours less in the afternoon than in the evening, so:
</span>x=5 \frac{1}{8} -1.75
<span>Since </span>\frac{1}{8} =0.125, we can rewrite our expression:
x=5.125-1.75
x=3.375

We can conclude that she works 3.375 hours in the evening, or expressed as a mixed fraction: 3 \frac{3}{8} hours.
3 0
2 years ago
What is the most precise name for quadrilateral ABCD with vertices A(-2,4), B(5,6), C(12,4) and D(5,2)?
Dmitry_Shevchenko [17]
I think its going to be around B or D
6 0
2 years ago
Read 2 more answers
Nora is running a race that is 26.2 miles. She is running at a speed of 8 miles per hour. She has completed 3/4 of the race. How
Nataly [62]
The answer to this problem would be about 4 hours
6 0
2 years ago
A friend of mine is giving a dinner party. His current wine supply includes 10 bottles of zinfandel, 8 of merlot, and 11 of cabe
Vlada [557]

Answer:

a) 720, b) 475020, c) 69300, d) 0.146, e) 0.001

Step-by-step explanation:

It is given that my friend has 10 bottles of zinfandel, 8 of merlot, and 11 of cabernet.

a)

If he wants to serve 3 bottles of zinfandel and serving order is important, then the total number of ways is

10\times 9\times 8=720

Therefore if he wants to serve 3 bottles of zinfandel and serving order is important, then the total number of ways are 720.

b)

The total number of bottles is

10+8+11=29

Combination is defined as

^nC_r=\frac{n!}{r!(n-r)!}

where, n is total possible outcomes and r is selected outcomes.

we have to select 6 bottles out of 29. so,

^{29}C_{6}=475020

Therefore ff 6 bottles of wine are to be randomly selected from the 29 for serving, then the total number of ways are 475020.

c)

If we want to select 2 bottles of each variety, then total number of ways are

^{10}C_{2}\times ^{8}C_{2}\times ^{11}C_{2}=69300

Therefore if 6 bottles are randomly selected with two bottles of each variety, then the total possible ways are 69300.

d)

Probability is defined as

P=\frac{\text{Total outcomes}}{\text{Favorable outcomes}}

\frac{^{10}C_{2}\times ^{8}C_{2}\times ^{11}C_{2}}{^{29}C_{6}}=\frac{69300}{475020}\approx 0.146

Therefore the probability that two bottles of each variety being chosen is 0.146.

e)

If 6 bottles are randomly selected, then the probability that all of them are the same variety is

\frac{^{10}C_{6}+^{8}C_{6}+^{11}C_{6}}{^{29}C_{6}}=\frac{700}{475020}\approx 0.001

Therefore if 6 bottles are randomly selected, then the probability that all of them are the same variety is 0.001.

7 0
2 years ago
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