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Lynna [10]
2 years ago
13

The seasonal output of a new experimental strain of pepper plants was carefully weighed. The mean weight per plant is 15.0 pound

s, and the standard deviation of the normally distributed weights is 1.75 pounds. Of the 200 plants in the experiment, how many produced peppers weighing between 13 and 16 pounds
Mathematics
1 answer:
DanielleElmas [232]2 years ago
4 0

Answer:

There are 118 plants that weight between 13 and 16 pounds

Step-by-step explanation:

For any normal random variable X with mean μ and standard deviation σ : X ~ Normal(μ, σ)  

This can be translated into standard normal units by :  

Z = \frac{(X - \mu)}{\sigma}

Let X be the weight of the plant  

X ~ Normal( 15 , 1.75 )  

To find : P( 13 < X < 16 )  

= P(\frac{( 13 - 15 )}{1.75} < Z < \frac{( 16 - 15 )}{1.75})

= P( -1.142857 < Z < 0.5714286 )  

= P( Z < 0.5714286 ) - P( Z < -1.142857 )  

= 0.7161454 - 0.1265490  

= 0.5895965  

So, the probability that any one of the plants weights between 13 and 16 pounds is 0.5895965  

Hence, The expected number of plants out of 200 that will weight between 13 and 16 = 0.5895965 × 200

                                            = 117.9193  

Therefore, There are 118 plants that weight between 13 and 16 pounds.

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2 years ago
Suppose abby tracks her travel time to work for 60 days and determines that her mean travel time, in minutes, is 35.6. assume th
HACTEHA [7]
Given that:
mean,μ=35.6 min
std deviation,σ=10.3 min
we are required to find the value of x such that 22.96% of the 60 days have a travel time that is at least x.
using z-table, the z-score that will give us 0.2296 is:-1.99
therefore:
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7 0
2 years ago
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A carpool service has 2,000 daily riders. A one-way ticket costs $5.00. The service estimates that for each $1.00 increase to th
solmaris [256]

Answer:

Total number of riders that ride on carpool daily = 2000

Total Cost of one way ticket = $ 5.00

Total Amount earned if 2000 passengers rides daily on carpool = 2000 × 5

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If fare increases by $ 1.00

New fare = $5 + $1    

               = $6

Number of passengers riding on carpool = 2,000 - 100 = 1,900

If 1,900 passengers rides on carpool daily , total amount earned ,if cost of each ticket is $ 6 = 1900 × $6 = $11400

As we have to find the inequality which represents the values of x that would allow the carpool service to have revenue of at least $12,000.

For $ 1 increase in fare = (2,000 - 1 × 100) passengers

For $ x increase in fare, number of passengers = 2,000 - 100·x

                                                         = (2,000 - 100·x) passengers

New fare = 5 + x

New Fare × Final Number of passengers ≥ 12,000

(5+x)·(2,000 - 100 x) ≥ 12,000

5 (2,000 - 100 x) + x(2,000 - 100 x) ≥ 12,000

10,000 - 500 x + 2,000 x - 100 x² ≥ 12,000

100 - 5 x + 20 x - x² ≥ 120

- x² + 15 x +100 - 120 ≥ 0

-x² + 15 x -20 ≥ 0

x² - 15 x + 20 ≤ 0

⇒ x = 1.495

x ≥ $ 1.495, that is if we increase the fare by this amount or more than this the revenue will be at least 12,000 or more .

Also, f'(x) = 0 gives x = 7.5

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7 0
2 years ago
Find the perimeter of △CDE. Round your answer to the nearest hundredth. The perimeter is about units.
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Answer: 9.66\ units

Step-by-step explanation:

The triangle CDE is shown in the image attached.

The formula for calculate the distance between two points is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Then, we can calculate the lenght of each side of the triangle:

d_{CD}=\sqrt{(4-4)^2+(-5-(-1))^2}=4\ units\\\\d_{DE}=\sqrt{(4-2)^2+(-5-(-3))^2}=2.828\ units\\\\d_{CE}=\sqrt{(2-4)^2+(-3-(-1))^2}=2.828\ units

Therefore, the perimeter is:

P=4\ units+ 2.828\ units+2.828\ units=9.66\ units

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Answer:

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1. Measure the amount that Claudia herself drank.

2. Subtract that from the amount of water that the jug was filled with before the soccer game.

3. Find the difference of that and the current amount of water.

Step-by-step explanation:


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