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Salsk061 [2.6K]
2 years ago
13

I'm at a bookstore with $\$35$ in my pocket and a $20\%$-off coupon. What is the cost of the most expensive book I can buy with

my money and the coupon? (Assume that there are books of every possible price in the bookstore. It's a large bookstore!)
Mathematics
2 answers:
adoni [48]2 years ago
8 0

Answer:

$43.75

Step-by-step explanation:

Let x represent the cost of the book.  We have a 20% off coupon; this means we will pay 100-20 = 80% of the cost.

80% = 80/100 = 0.8; this means we the cost we pay will be represented using the expression 0.8x.

Since we only have $35, this gives us the equation

0.8x = 35

Divide both sides by 0.8:

0.8x/0.8 = 35/0.8

x = $43.75

butalik [34]2 years ago
7 0

Answer:

The cost of the most expensive book which he can buy with his money is less than or equal to 43.5

Step-by-step explanation:

Given : I'm at a bookstore with $35 in my pocket and a 20%-off coupon.

To Find: . What is the cost of the most expensive book I can buy with my money and the coupon?

Solution :

let the cost of most expensive book be x

Since there is 20 % of on every book

So, After 20 % off on the most expensive

The cost will be :  x  - (x of 20%)

                             =x-\frac{20}{100} x

                             =\frac{80}{100} x

                             =\frac{4}{5} x

Since we are given that he has only $35 so he cannot pay more than 35

so, equation becomes :

\frac{4}{5} x\leq 35

x\leq\frac{5*35}{4}

x\leq\frac{175}{4}

x\leq43.5

So , the cost of the most expensive book which he can buy with his money is less than or equal to 43.5




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Answer:

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Step-by-step explanation:

The regression line has the following format:

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In which b is the slope(how much each mile costs) and a is the fixed number of miles flown.

In this problem, we have that:

a = 24000, b = 10. So

y = 10x + 24000

A person who spent $ 2000 is predicted to have flown:

This is y when x = 2000.

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So the correct answer is:

c) 44000 miles

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Answer: visit the US Bureau of Labor Statistics website to find information on both careers

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Step-by-step explanation: there is none

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2 years ago
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Line GH contains points G(–2, 6) and H(5, –3). What is the slope of ?
alexgriva [62]

We will use the slope formula and fill it in accordingly.

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Our x2 is 5 and x1 is -2; our y2 is -3 and y1 is 6

m=\frac{-3-6}{5-(-2)}=\frac{-9}{7}.

The slope of your line is -9/7

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Ms. Banerjee bought a car for $22,500. The amount she paid for her new car was twice the amount she paid for her previous car, w
bagirrra123 [75]

You didn't say if the car bought is the new car or the old car so I'm assuming the car bought for $22,500 is the new car.

You divide 22,500 by 2 to get the cost of the old car. When you do this, you find out the old car costed $11,250.

the equation is 22,500/2=p


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2 years ago
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Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
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