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Blizzard [7]
2 years ago
8

Anton Leeuwenhoek Devised a primitive microscope to observe a sample of his tooth scrapings. How did this help contribute it to

cell theory?
A-it help to show that cells cannot function independently. B it helped to show that some bacteria can swim like fish. C- it help to show that some bacteria are just one cell. D-it help to show that cells can be created into thin air.
Biology
1 answer:
4vir4ik [10]2 years ago
6 0

Answer:

C- it help to show that some bacteria are just one cell.

Explanation:

Anton Leeuwenhoek was the first scientist who observed the presence of bacteria in his tooth scratch under the microscope made by himself. At that time there was no concept of bacteria and he named those small creatures as animalcules which were later termed as bacteria.

Leeuwenhoek during 1670s  sent the details of his experimentation on algae and bacteria to Royal Society of London.

It was due to his that primitive experiment that made the discovery of bacteria and make it known to other scientists. Therefore option C is the best option that demonstrates that bacteria are single celled organisms that are very minute. When we look at cell theory there is a postulate that shows that cell is the fundamental unit of function and structure  of all living organisms. So, the work of Anton Leeuwenhoek holds substantial importance in the formulation of cell theory.

Hope it helps!


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A student examining leaf cross sections under a microscope finds many loosely packed cells with relatively thin cell walls. The
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The answer is spongy mesophyll.

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Identify the ways in which a rooftop garden can reduce the heat absorbed, compared to an asphalt roof. Select the three correct
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plants release water vapor

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The state of health and functioning of the liver is often assessed with dye-tracer techniques. The dye used most frequently is b
elena-s [515]

Answer

1.Radioactive or chemical decay

2. X(t) = Xoe^-kt

lnY(t) = -t + lnYo

4. 6.07mg

Explanation:

Let the liver and and blood compartment be represented by the symbol L and B respectively

For the liver

Suppose a first Order removal process started with an amount X, in which amount b disappeared in time t, the process is decay process which can be represented as follows,

∫dX/dt = -K1X

By rearrangement and integration;

∫dX/X = -K1t

ln X = -K1t + C

Since At t= 0, X = Xo then

C = lnXo

The equation becomes:

lnX = -K1t + lnXo

lnX - lnXo = -K1t

ln(X/Xo) = -K1t

X/Xo = e^-kt

X(t) = Xoe^-kt

X(t) = Xoe^-0.5t........(2)

Similarly for B (blood), suppose a first order flow flow of the dye move from the blood to the liver, let Y be the initial concentration, and amount b that has flown to the liver in time t

B---------> B(t)

t=0 Yo 0

t=t. Y-b. b

dY/dt = -K12(Y-b)...........(3)

Let Y-b = Y(t)

∫dY/dt = -∫K12t

By rearrangement and integration;

∫dy/Y(t) = ∫-K12dt

lnY(t) = -K12t + C1

at t= 0, C1 = ln(Yo)

Therefore ln Y(t) = -K12t + lnYo

But K12 =1

ln Y(t) = -t + lnYo.............(4)

(3) The assumptions used here

is that of a decay for the liver . The amount remaining taking as the amount of a substance

(4) using the equation 2,

X(t)= Xo e^-K1t........(2)

For time t = 1hour, and an initial amount X = 10mg, K = 0.5

X(t) = 10× e^-0.5

X(t) = 10 × 0.607

X(t) = 6.07mg

(5) within the scope of information presented, I have no data to make this judgment.

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