Answer: Kai
Step-by-step explanation:
I did the assignment and got it correct
12 divided by 4 equals to 3
she paints 3 wall per hour
the answer is : the remaining wall will take her 1 hour to paint
Answer:
c. Minimize P,d1+; 5x1 + 3x2 + d1+ = 150
Step-by-step explanation:
5x1 + 3x2 = 150. To convert an equality, we simply add an “artificial” variable (d1) to the equation: 5X1 + 3X2 + d1 = 150 An artificial variable is a variable that has no physical meaning in terms of a real-world LP problem. It simply allows us to create a basic feasible solution to start the simplex algorithm. An artificial variable is not allowed to appear in the final solution to the problem. Here in this problem to avoid over utilization, we introduce this artifical variable.
Order does not matter so use "n choose k" formula is used to find number of unique combinations.
c=n!/(k!(n-k)!) where n is total possible choices and k is number of selections.
c=4!/(2!(4-2)!)
c=4!/(2!2!)
c=24/(2*2)
c=24/4
c=6
So there are 6 different two topping options when there are four different toppings to choose from.
Answer:
The 95% confidence interval for the population variance is ![\left[0.219, \hspace{0.1cm} 0.807\right]\\\\](https://tex.z-dn.net/?f=%5Cleft%5B0.219%2C%20%5Chspace%7B0.1cm%7D%200.807%5Cright%5D%5C%5C%5C%5C)
The 95% confidence interval for the population mean is ![\left [15.112, \hspace{0.3cm}15.688\right]](https://tex.z-dn.net/?f=%5Cleft%20%5B15.112%2C%20%5Chspace%7B0.3cm%7D15.688%5Cright%5D)
Step-by-step explanation:
To solve this problem, a confidence interval of 
for the population variance will be calculated.
Then, the confidence interval for the population variance is given by:
![\left [\frac{(n-1)S^2}{\chi^2_{\left (\frac{\alpha}{2};n-1\right )}}, \hspace{0.3cm}\frac{(n-1)S^2}{\chi^2_{\left (1-\frac{\alpha}{2};n-1\right )}} \right ]\\\\](https://tex.z-dn.net/?f=%5Cleft%20%5B%5Cfrac%7B%28n-1%29S%5E2%7D%7B%5Cchi%5E2_%7B%5Cleft%20%28%5Cfrac%7B%5Calpha%7D%7B2%7D%3Bn-1%5Cright%20%29%7D%7D%2C%20%5Chspace%7B0.3cm%7D%5Cfrac%7B%28n-1%29S%5E2%7D%7B%5Cchi%5E2_%7B%5Cleft%20%281-%5Cfrac%7B%5Calpha%7D%7B2%7D%3Bn-1%5Cright%20%29%7D%7D%20%5Cright%20%5D%5C%5C%5C%5C)
Thus, the 95% confidence interval for the population variance is:![\\\\\left [\frac{(19-1)(0.6152)^2}{32.852}, \hspace{0.1cm}\frac{(19-1)(0.6152)^2}{8.907} \right ]=\left[0.219, \hspace{0.1cm} 0.807\right]\\\\](https://tex.z-dn.net/?f=%5C%5C%5C%5C%5Cleft%20%5B%5Cfrac%7B%2819-1%29%280.6152%29%5E2%7D%7B32.852%7D%2C%20%5Chspace%7B0.1cm%7D%5Cfrac%7B%2819-1%29%280.6152%29%5E2%7D%7B8.907%7D%20%5Cright%20%5D%3D%5Cleft%5B0.219%2C%20%5Chspace%7B0.1cm%7D%200.807%5Cright%5D%5C%5C%5C%5C)
On other hand,
A confidence interval of for the population mean will be calculated
\![\left[ \bar X - T_{(\alpha/2;n-1}\sqrt{\frac{\S^2}{n}}, \hspace{0.3cm}\bar X + T_{(\alpha/2;n-1}\sqrt{\frac{\S^2}{n}} \right ]\\\\](https://tex.z-dn.net/?f=%5Cleft%5B%20%5Cbar%20X%20-%20T_%7B%28%5Calpha%2F2%3Bn-1%7D%5Csqrt%7B%5Cfrac%7B%5CS%5E2%7D%7Bn%7D%7D%2C%20%5Chspace%7B0.3cm%7D%5Cbar%20X%20%2B%20T_%7B%28%5Calpha%2F2%3Bn-1%7D%5Csqrt%7B%5Cfrac%7B%5CS%5E2%7D%7Bn%7D%7D%20%5Cright%20%5D%5C%5C%5C%5C)
Thus, the 95\% confidence interval for the population mean is:![\\\\\left [15.40 - 2.093\sqrt{\frac{(0.6152)^2}{19}}, \hspace{0.3cm}15.40 + 2.093\sqrt{\frac{(0.6152)^2}{19}} \right ]=\left [15.112, \hspace{0.3cm}15.688\right] \\\\](https://tex.z-dn.net/?f=%5C%5C%5C%5C%5Cleft%20%5B15.40%20-%202.093%5Csqrt%7B%5Cfrac%7B%280.6152%29%5E2%7D%7B19%7D%7D%2C%20%5Chspace%7B0.3cm%7D15.40%20%2B%202.093%5Csqrt%7B%5Cfrac%7B%280.6152%29%5E2%7D%7B19%7D%7D%20%5Cright%20%5D%3D%5Cleft%20%5B15.112%2C%20%5Chspace%7B0.3cm%7D15.688%5Cright%5D%20%5C%5C%5C%5C)
