Question

Which equation is the inverse of y=x2 + 16?

Answer 1

Answer:

y-16=x^2

Step-by-step explanation:

Answer 2

Answer:

$f^{-1}(x)=\pm\sqrt{x-16}$

Step-by-step explanation:

The given equation is $y=x^2+16$

Interchange the positions of x and y

$x=y^2+16$

Now, solve this equation for y. That would be the inverse of this function.

Subtract 16 to both sides of the equation

$x-16=y^2$

Take square root both sides

$y=\pm\sqrt{x-16}$

This is the inverse of the given function.

$f^{-1}(x)=\pm\sqrt{x-16}$