What is this question asking for as an answer? It only has the robot's situation listed, not what the question is. Could you please put the question into further detail?
Answer:
- P(≥1 working) = 0.9936
- She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.
Step-by-step explanation:
1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...
... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936
2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.
If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.
This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.
_____
My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)
Chance of winning $100 = 1/1000
<span>chance of winning $50 = 5/1000 = 1/200 </span>
<span>cost of ticket = -1 </span>
<span>E[x] = 100* 1/1000 + 50* 1/200 -1 </span>
<span>= 0.1 + 0.25 - 1 = -0.65
Hope this helps</span>
v=gt,
Initial value when time t=0, v=g*0=0.
t=0 s, v=0 m/s means that object’s initial velocity 0 m/s.
v=gt, and g is a constant g=9.8 m/s². We can write v=9.8*t.
Rate of change 9.8 means the acceleration due to gravity is 9.8 m/s².
Answer: C. The initial value is 0. That means that object’s initial velocity 0 m/s. The rate of change is 9.8. That means the acceleration due to gravity is 9.8 m/s2.
Answer: Explanation and answer is attached.
Step-by-step explanation: