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Dovator [93]
2 years ago
12

Be sure to answer all parts. Predict the effect of decreasing the temperature on the amounts of reactants in the following react

ions: (a) C2H2(g) + H2O(g) ⇌ CH3CHO(g) ΔH o rxn = −151 kJ The amounts of reactants stay the same. The amounts of reactants decrease. The amounts of reactants increase. (b) CH3CH2OH(l) + O2 (g) ⇌ CH3CO2H(l) + H2O(g) ΔH o rxn = −451 kJ The amounts of reactants stay the same. The amounts of reactants decrease. The amounts of reactants increase. (c) 2 C2H4(g) + O2(g) ⇌ 2 CH3CHO(g) (exothermic) The amounts of reactants stay the same. The amounts of reactants decrease. The amounts of reactants increase. (d) N2O4(g) ⇌ 2 NO2(g) (endothermic) The amounts of reactants decrease. The amounts of reactants stay the same. The amounts of reactants increase.
Chemistry
1 answer:
lianna [129]2 years ago
3 0

Answer:

(a) The amounts of reactants decrease.

(b) The amounts of reactants decrease.

(c) The amounts of reactants decrease.

(d) the amounts of reactants increase.

Explanation:

  • Le Châtelier's principle states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

<em>(a) C₂H₂(g) + H₂O(g) ⇌ CH₃CHO(g) ΔH°rxn = − 151 kJ.</em>

  • Since, ΔH is a negative value, the reaction is exothermic reaction.

So, the reaction can be represented as:

C₂H₂(g) + H₂O(g) ⇌ CH₃CHO(g) + heat.

As the temperature is decreases, it is like that decreasing the concentration of products side, that shifts the reaction towards the right side (products side) to attain the equilibrium again. So, the amounts of reactants decrease.

So, the right choice is reaction is: The amounts of reactants decrease.

<em>(b) CH₃CH₂OH(l) + O₂ (g) ⇌ CH₃CO₂H(l) + H₂O(g) ΔH°rxn = − 451 kJ.</em>

  • Since, ΔH is a negative value, the reaction is exothermic reaction.

So, the reaction can be represented as:

CH₃CH₂OH(l) + O₂ (g) ⇌ CH₃CO₂H(l) + H₂O(g) + heat.

As the temperature is decreases, it is like that decreasing the concentration of products side, that shifts the reaction towards the right side (products side) to attain the equilibrium again. So, the amount of reactants decrease.

So, the right choice is reaction is: The amounts of reactants decrease.

<em>(c) 2C₂H₄(g) + O₂(g) ⇌ 2CH₃CHO(g) (exothermic).</em>

  • Since, the reaction is exothermic reaction.

So, the reaction can be represented as:

2C₂H₄(g) + O₂(g) ⇌ 2CH₃CHO(g) + heat.

As the temperature is decreases, it is like that decreasing the concentration of products side, that shifts the reaction towards the right side (products side) to attain the equilibrium again. So, the amounts of reactants decrease.

So, the right choice is reaction is: The amounts of reactants decrease.

<em>(d) N₂O₄(g) ⇌ 2NO₂(g) (endothermic).</em>

  • For endothermic reaction, it can be represented as:

N₂O₄(g) + heat ⇌ 2NO₂(g)

As the temperature is decreased, it is like that decreasing the concentration of reactants side, that shifts the reaction towards the lift side (reactants side) to attain the equilibrium again. So, the amounts of reactants increase.

So, the right choice is reaction is: the amounts of reactants increase.

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Answer:

The answer to your question is     V2 = 825.5 ml

Explanation:

Data

Volume 1 = 750 ml

Temperature 1 = 25°C

Volume 2= ?

Temperature 2 = 55°C

Process

Use the Charles' law to solve this problem

                V1/T1 = V2/T2

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                V2 = V1T2 / T1

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T1 = 25 + 273 = 298°K

T2 = 55 + 273 = 328°K

-Substitution

                V2 = (750 x 328) / 298

-Simplification

                V2 = 246000 / 298

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                V2 = 825.5 ml

             

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<u>Answer:</u>

<u>For a:</u> The number of inner electrons, outer electrons and valence electrons are 28, 7 and 7 respectively.

<u>For b:</u> The number of inner electrons, outer electrons and valence electrons are 54, 1 and 1 respectively.

<u>For c:</u> The number of inner electrons, outer electrons and valence electrons are 23, 1 and 1 respectively.

<u>For d:</u> The number of inner electrons, outer electrons and valence electrons are 36, 2 and 2 respectively.

<u>For e:</u> The number of inner electrons, outer electrons and valence electrons are 2, 7 and 7 respectively.

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Outer shell electrons are the electrons which are not tightly held by the electrons. They are called as valence electrons. The electrons present in the highest principle quantum number are known as valence electrons.

Inner shell electrons are the electrons which are tightly held by the electrons. They are called as core electrons.

Inner electrons = Total number of electrons - Valence electrons

Total number of electrons in an atom is equal to the atomic number of the element.

For the given options:

  • <u>Option a:</u>  Bromine (Br)

Bromine is the 35th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^5

Highest principle quantum number is 4

Number of valence electrons = 7

Number of outer electrons = 7

Number of inner electrons = 35 - 7 = 28

  • <u>Option b:</u>  Cesium (Cs)

Cesium is the 55th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^66s^1

Highest principle quantum number is 6

Number of valence electrons = 1

Number of outer electrons = 1

Number of inner electrons = 55 - 1 = 54

  • <u>Option c:</u>  Chromium (Cr)

Chromium is the 24th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^13d^{5}

Highest principle quantum number is 4

Number of valence electrons = 1

Number of outer electrons = 1

Number of inner electrons = 24 - 1 = 23

  • <u>Option d:</u>  Strontium (Sr)

Strontium is the 38th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^2

Highest principle quantum number is 5

Number of valence electrons = 2

Number of outer electrons = 2

Number of inner electrons = 38 - 2 = 36

  • <u>Option e:</u>  Fluorine (F)

Fluorine is the 9th element of the periodic table having electronic configuration of 1s^22s^22p^5

Highest principle quantum number is 2

Number of valence electrons = 7

Number of outer electrons = 7

Number of inner electrons = 9 - 7 = 2

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