All categories

1 year ago

Assignment: Using Punnett Squares Exploration

Biology

2 answers:

WINSTONCH [101]1 year ago

5 0

Answer:

Case I

Genotypic Ratio – RR: Rr = 2: 2 = 1: 1

Phenotypic Ratio – All the offspring are red in color as R is dominant over r

Case II

Genotypic Ratio – RR: Rr: rr = 1: 2: 1

Phenotypic Ratio – All RR and Rr are red in color while rr is of different color, thus the phenotypic ratio is Red offspring : White offspring = 3:1

Case III

Genotypic Ratio – All offspring’s are of genotpe rr

Phenotypic Ratio – All offsprings are of white color

Explanation:

Case I – Homozygous red bull (RR) and a heterozygous red cow (Rr)

(R ) is dominant over ( r )

The punnet square for the cross between the Homozygous red bull (RR) and heterozygous red cow (Rr) is as follows -

R R

R RR RR

r Rr Rr

Genotypic Ratio – RR: Rr = 2: 2 = 1: 1

Phenotypic Ratio – All the offspring are red in color as R is dominant over r

Case II - heterozygous red bull (Rr) and a heterozygous red cow (Rr)

The punnet square for the cross between the heterozygous red bull (Rr) and a heterozygous red cow (Rr) is as follows -

R r

R RR Rr

r Rr rr

Genotypic Ratio – RR: Rr: rr = 1: 2: 1

Phenotypic Ratio – All RR and Rr are red in color while rr is of different color, thus the phenotypic ratio is Red offspring : White offspring = 3:1

Case III - homozygous white bull (rr) and a homozygous white cow (rr)

The punnet square for the cross between the homozygous white bull (rr) and a homozygous white cow (rr) is as follows -

r r

r rr rr

Genotypic Ratio – All offspring’s are of genotpe rr

Phenotypic Ratio – All offsprings are of white color

amm18121 year ago

3 0

Answer:

Explanation:

Genotype 1:

2/4 is RR so RR is 50%

2/4 is Rr so Rr is 50%

Phenotype:

Not enough info for that

Genotype 2:

1/4 is RR so RR is 25%

2/4 is Rr so Rr is 50%

1/4 is rr so rr is 25%

Phenotype:

Genotype 3:

4/4 is rr so rr is 100%

Phenotype:

You might be interested in

You want to test which size of soccer (football) ball is easiest to juggle with your feet. You test a size 3, size 4 and a size

Semenov [28]

Answer:

independent variable: size of soccer ball

dependent variable: period of time the balls stay in the air

control variable: parts of the body used to juggle the ball

Explanation:

The independent variable is the manipulatable variable supplied into an experiment. It is a variable that directly affects the dependent variable.

The independent variable is the outcome variable. It is the variable that is primarily measured from experiments whose value depends on the value of the independent variable.

The control variables are those that are kept constant throughout the course of experiments. In other words, they do not directly affect experimental outcomes.

Hence, in the illustration;

independent variable: size of soccer ball

dependent variable: period of time the balls stay in the air

control variable: parts of the body used to juggle the ball

4 0

2 years ago

Suppose that Gene B occurs in a sea turtle gene pool where the frequency of the B1 allele is 0.5 and the frequency of the B2 all

disa [49]

Answer:

Frequency of the B3 allele $= 0.1$

Explanation:

The allele frequencies in a given population remain constant which means that every generation will have the same gene pool across the generations. As per Hardy Weinberg’s first equilibrium equation, the sum of frequency of all the alleles at a given locus is equal to one

Thus, if "p" represents the frequency of B1 allele and "q" represents the frequency of B2 allele and "r" represents the allele for B3 allele. Then, sum or "p", "q" and "r" is equal to one.

$p+q+r = 1\\$

Substituting the given values, we get -

$0.5 + 0.4 + r = 1\\0.9 + r = 1\\r = 1-0.9\\r = 0.1$

5 0

2 years ago

How do sodium and potassium leak channels play a role in the development of the negative membrane potential of the axolemma (pla

kirza4 [7]

The plasma membrane of axon is called axolemma. The potassium and sodium leak channels leak the sodium and potassium ions inside the cell respectively. The leak channels provide the constant movement of ions across the membrane. Potassium and sodium ions are positively charged, thus entry of positively charged ions inside the cell makes the cell more positively charged than the environment outside the cell. The environment outside the cell becomes more negatively charged. This leads in the negative membrane potential of axolemma.

7 0

2 years ago

How does the construction of dams positively affect natural resources?

Vadim26 [7]

Answer:

a)by providing water for irrigation and restoring trees to areas where forests once existed

Explanation:

3 0

2 years ago

Suppose a human blood cell containing a 0.9 percent solute concentration were put into a container of 0 percent solute solution

Vladimir [108]

Answer and explanation:

If a human blood cell with a 0.9% solute concentration were to be put into a container of 0% solute solution, the cell would get BIGGER.

The cell contains a more concentrated solution than the solution in the container. The difference in concentration would produce an osmotic gradient that would cause water from the container to get inside the cell to even the concentrations - this is going to make the cell much bigger because the entering water would bloat the cell.

In this example, the solution in the container is hypotonic in relation to the cell, while the solution inside the cell is hypertonic in relation to the solution in the container. This is why the water will be moving from outside of the cell to the inside of the cell.

6 0

1 year ago