The rectangle below has an area of 12y^2+21y^5 square meters The width of the rectangle (in meters) is equal to the gcf of 12y^2

Question

navik [9.2K]

2 years ago

3

The rectangle below has an area of 12y^2+21y^5 square meters The width of the rectangle (in meters) is equal to the gcf of 12y^2

and 21y^5

Mathematics

1 answer:

ahrayia [7] · Answer 1 · 2023-09-26T06:00:44+03:00

ahrayia [7]2 years ago

8 0

Answer:

<h2>length = (4+7y³)</h2><h2>width = 3y²</h2>

Step-by-step explanation:

$12y^2=3y^2\cdot4\\\\21y^5=3y^2\cdot7y^3\\\\GCF(12y^2,\ 21y^5)=3y^2\leftarrow width\\\\\text{The formula of an area of a rectangle:}\\\\A=lw\\\\l-length\\w-width\\\\\text{We have the area of the rectangle:}\ A=12y^2+21y^5=3y^2(4+7y^3)\\\\\text{Conclusion:}\\\\length=\\width=3y^2$