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IgorC [24]
2 years ago
15

If 200 mL of water is evaporated from 400 mL of 0.5 M aqueous salt solution, what is the resulting concentration? 1. 2.5 × 10−1

M 2. 2.5 × 101 M 3. 2.5 × 100 M 4. 2.5 × 10−2 M 5. None of these
Chemistry
1 answer:
ikadub [295]2 years ago
5 0

Answer:

None of these

Explanation:

Using the dilution formula;

M1V1 = M2V2

where M1 is the initial concentration, V1 is the initial volume, M2 is the concentration attained while V2 is the new volume.

Therefore;

M2 = M1V1/V2

     = (400 mL × 0.5) / 200 mL

     = 1 M

Therefore, the resulting concentration is 1M

Thus, the correct answer is "none of these"

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An amount of solid barium chloride, 20.8 g, is dissolved in 100 g water in a coffee-cup calorimeter by the reaction: BaCl2 (s) 
mamaluj [8]

Answer : The enthalpy change during the reaction is -6.48 kJ/mole

Explanation :

First we have to calculate the heat gained by the reaction.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat gained = ?

m = mass of water = 100 g

c = specific heat = 4.04J/g^oC

T_{final} = final temperature = 26.6^oC

T_{initial} = initial temperature = 25.0^oC

Now put all the given values in the above formula, we get:

q=100g\times 4.04J/g^oC\times (26.6-25.0)^oC

q=646.4J

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles barium chloride = \frac{\text{Mass of barium chloride}}{\text{Molar mass of barium chloride}}=\frac{20.8g}{208.23g/mol}=0.0998mole

\Delta H=-\frac{646.4J}{0.0998mole}=-6476.95J/mole=-6.48kJ/mole

Therefore, the enthalpy change during the reaction is -6.48 kJ/mole

8 0
2 years ago
If a 0.4856 gram sample of khp is dissolved in sufficient water to prepare 250 ml of solution, and 25 ml of the solution require
dangina [55]

Mass of potassium hydrogen pthalate KHP is 0.4856 g, its molar mass is 204.22 g/mol, number of moles of KHP can be calculated as follows:

n=\frac{m}{M}

Here, m is mass and M is molar mass, putting the values,

n=\frac{0.4856 g}{204.22 g/mol}=0.00237 mol

This will be number of moles of NaOH at equivalent point.

Detailed calculations:

Molarity is defined as number of moles in 1 L of solution, for 250 mL of solution, molarity will be:

M=\frac{0.00237 mol}{250 \times 10^{-3}L}=0.009511 M

For 25 mL, apply dilution law as follows:

M_{1}V_{1}=M_{2}V_{2}

Putting the values,

0.009511\times 250=M_{2}\times 25 mL

On rearranging,

M_{2}=\frac{0.009511\times 250}{25}=0.09511 M

Convert molarity into number of moles,

n=M\times V=0.09511 mol/L\times 25\times 10^{-3}L=0.00237 mol

At equivalent point, number of moles of KHP will be equal to NaOH, thus, number of moles of NaOH will be 0.00237 mol.

Calculation for molarity:

Volume of NaOH is 18.75 mL, thus, molarity can be calculated as follows:

M=\frac{n}{V}

Putting the values,

M=\frac{0.00237 mol}{18.75\times 10^{-3}L}=0.1264 M

Therefore, molarity of NaOH is 0.1264 M

7 0
2 years ago
Groups of atoms that are added to carbon backbones and give them unique properties are known as
Irina-Kira [14]

Answer:

             Groups of atoms that are added to carbon backbones and give them unique properties are known as <u>Functional Groups</u>.

Explanation:

                   In organic chemistry they are called as Functional Group because they are the active part of a molecule. These groups give a unique characteristic to molecule both chemically and physically. Also, each functional group represent a different class of compounds.

Examples:

S No.                          Functional Group                                 Name

1                                   R--X                                             Alkyl Halides

2                                   R--OH                                          Alcohols

3                                  R--NH₂                                         Amines

4                                  R--O--R                                         Ethers

5                                   R--CO--R                                      Ketones

6                                   R--CO--H                                     Aldehydes

7                                  R--CO--OH                                  Carboxylic acids

8                                   R--CO--X                                     Acid Halides

10                                R--CO--NR₂                                 Acid Amides

11                                 R--CO-OR'                                  Esters

3 0
2 years ago
The complex ion, [ni(nh3)6] 2+, has a maximum absorption near 580 nm. calculate the crystal field splitting energy (in kj/mol) f
Wewaii [24]
In given data:
maximum absorption wavelength λ = 580 nm = 580 x 10⁻⁹ m
write the equation to find the crystal field splitting energy:
E = hC / λ 
Here, E is the crystal field splitting energy, h = 6.63 x 10⁻³⁴ J.sec is Planck's constant and C = 3 x 10⁸ m/sec is speed of light. 
substitute in the equation above:
E = (6.64 x 10⁻³⁴ x 3 x 10⁸) / (580 x 10⁻⁹) = 3.43 x 10⁻¹⁹J
This crystal field splitting energy is for 1 ion.
Number of atoms in one mole, NA = 6.023 x 10²³ 
to calculate the crystal field splitting energy for one mole:
E(total) = E x NA
             = (3.43 x 10⁻¹⁹) x (6.023 x 10²³) = 206 kJ/ mole



 
5 0
2 years ago
The powder-based packet to purify water failed for a number of reasons including Select one: a. Rust b. Expense c. Sales personn
grin007 [14]

Answer:

D. Contamination

8 0
2 years ago
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